2 = $1.45
1 = $0.725
anything to ask please pm me
Step-by-step explanation:

The simplest method is "brute force". Calculate each term and add them up.
∑ = 3(1) + 3(2) + 3(3) + 3(4) + 3(5)
∑ = 3 + 6 + 9 + 12 + 15
∑ = 45

∑ = (2×1)² + (2×2)² + (2×3)² + (2×4)²
∑ = 4 + 16 + 36 + 64
∑ = 120

∑ = (2×3−10) + (2×4−10) + (2×5−10) + (2×6−10)
∑ = -4 + -2 + 0 + 2
∑ = -4
4. 1 + 1/4 + 1/16 + 1/64 + 1/256
This is a geometric sequence where the first term is 1 and the common ratio is 1/4. The nth term is:
a = 1 (1/4)ⁿ⁻¹
So the series is:

5. -5 + -1 + 3 + 7 + 11
This is an arithmetic sequence where the first term is -5 and the common difference is 4. The nth term is:
a = -5 + 4(n−1)
a = -5 + 4n − 4
a = 4n − 9
So the series is:

Answer:
C = 420/h + 400
Step-by-step explanation:
Let s be the side of the square base.
Let h be the height
Volume = s*h
20 = s*h
s = 20/h
Cost of glass is
5(20/h) + 5(4* h*20/h)
= 100/h + 400
Cost of frame is
2*4(20/h) + 2*4(20/h)
= 160/h + 160/h
= 320/h
Total cost = C
C = cost of glass + cost of frame
C = 100/h + 400 + 320/h
C = 420/h + 400
Start with how much profit they are making off each race entry. People pay $55 to race, but $15 of that is expenses so they are only profiting $40 for each entry. Now write one side of the equality. They start with $10,000 in donations, and then have a $40 profit for each race entry. So 10,000+40x. X will represent the unknown number of race entries. What do we want that expression to be equal to? We want 10000+40x>55000. It can also be greater than or equal to, not just greater than.
Solve for x. Subtract 10000 from each side resulting in 40x>45000. Divide each side by 40 to solve for x. X>1125. X needs to bbe greater than or equal to 1125. If there are 1125 race entries, the charity will profit exactly $55000, so the lowest number of race entries is 1125
Answer:
Yes, between 0.84 seconds and 0.85 seconds after the shot is launched.
Step-by-step explanation:

But, the shot is made before two tenths of a second or 0.2 seconds therefore modified equation for ball height is :

Now for the shot to be blocked,the height of shot blocker must be greater than the height of the ball which is shot before 0.2 seconds :

Hence, the shot was blocked between 0.84 and 0.85 seconds after the shot is launched.