Answer:
500 lb
Step-by-step explanation:
You have to make a proportion:

77 lb is part of the whole weight ( which we don't know) so 77 will go on top
The problem tells us that 15.4% of the total weight is pecans so 15.4 will go over 100 (since % are out of 100)

Then you cross multiply giving you: 7700 = 15.4x
then you divide 15.4 to both sides to isolate x which will give you 500
I'll just show you how to make a frequency table using the above data.
We will group the data into class intervals and determine the frequency of the group.
<span>8 12 25 32 45 50 62 73 80 99 4 18 9 39 36 67 33
</span>
smallest data value = 4
highest data value = 99
difference = 99 - 4 = 95
number of data = 17
Let us assign a class interval of 20.
Class Interval Tally Frequency
0-20 8, 12, 4, 18, 9, 5
21-40 25, 32, 39, 36, 33 5
41-60 45, 50, 67 3
61-80 62, 73, 80 3
81-100 99 1
That is how a frequency table look like. Usually, under the Tally column, tick marks are written instead of the numbers but for easier monitoring, I used the numbers in the data set.
Answer:
3.85 hours
Step-by-step explanation:
We have that the model equation in this case would be of the following type, being "and" the concentration of bacteria:
y = a * e ^ (b * t)
where a and b are constants and t is time.
We know that when the time is 0, we know that there are 100,000 bacteria, therefore:
100000 = a * e ^ (b * 0)
100000 = a * 1
a = 100000
they tell us that when the time is 2 hours, the amount doubles, that is:
200000 = a * e ^ (b * 2)
already knowing that a equals 100,000
e ^ (b * 2) = 2
b * 2 = ln 2
b = (ln 2) / 2
b = 0.3465
Having the value of the constants, we will calculate the value of the time when there are 380000, that is:
380000 = 100000 * (e ^ 0.3465 * t)
3.8 = e ^ 0.3465 * t
ln 3.8 = 0.3465 * t
t = 1.335 / 0.3465
t = 3.85
That is to say that in order to reach this concentration 3.85 hours must pass
Answer:
Standard deviation = 8.27 percent
Step-by-step explanation:
Average = (Σx)/N
The average is the sum of variables divided by the number of variables.
x = each variable
N = number of variables = 5
Let the unknown percent be y
6 = (8 - 3 + 12 + 17 + y)/5
y = 30 - 34 = - 4
The standard deviation is the square root of variance. And variance is an average of the squared deviations from the mean.
Mathematically,
Standard deviation = σ = √[Σ(x - xbar)²/N]
x = each variable
xbar = mean = 6 percent
N = number of variables
σ = √[{(8 - 6)² + (-3 - 6)² + (12 - 6)² + (17 - 6)² + (-4 - 6)²}]/(5)]
σ = √[[(2)² + (-9)² + (6)² + (11)² + (-10)²]/(5)]
σ = √[(4 + 81 + 36 + 121 + 100)/(5)] = √(342/5) = 8.27 percent.