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-BARSIC- [3]
2 years ago
6

A 0.652-g sample of a pure strontium halide reacts with excess sulfuric acid. the solid strontium sulfate formed is separated, d

ried, and found to weigh 0.755 g. what is the formula of the original halide?
Chemistry
1 answer:
seraphim [82]2 years ago
4 0

Answer:

The formula of the original halide is SrCl₂.

Explanation:

  • The balanced equation of this reaction is:

SrX₂ + H₂SO₄ → SrSO₄ + 2 HX, where X is the halide.

  • From the equation stichiometry, 1.0 mole of strontium halide will result in 1.0 mole of SrSO₄.
  • The number of moles of SrSO₄ <em>(n = mass/molar mass) </em>= (0.755 g) / (183.68 g/mole) = 4.11 x 10⁻³ mole.
  • The number of moles of SrX are  4.11 x 10⁻³ moles from the stichiometry of the balanced equation.
  • n = mass / molar mass, n =  4.11 x 10⁻³ moles and mass = 0.652 g.
  • The molar mass of SrX₂ = mass / n = (0.652) / (4.11 x 10⁻³ moles) = 158.62 g/mole.
  • The molar mass of SrX₂ (158.62 g/mole) = Atomic mass of Sr (87.62 g/mole) + (2 x Atomic mass of halide X).
  • The atomic mass of halide X = (158.62 g/mole) - (87.62 g/mole) / 2 = 71 / 2  g/mole = 35.5 g/mole.
  • This is the atomic mass of Cl.
  • <em>So, the formula of the original halide is SrCl₂</em>.
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Standard Hydrogen Electrode consists of platinum wire fused in a glass tube and a platinum plate coated with finely divided plat
iris [78.8K]

Answer:

To increase surface area of the platinum electrode which results in superior quality and action of the electrodes as opposed to normal platinum electrodes.

Explanation:

Platinization of Platinum is the process of covering platinum electrode with a layer of platinum black. Platinum black is a finally divided form of platinum, optimized for catalysing the addition of hydrogen to unsaturated organic compound. This increases the surface area of the platinum electrodes and therefore exhibits action superior to that of normal electrodes.

5 0
2 years ago
A 0.3870-g sample of a compound known to contain only carbon, hydrogen, and oxygen was burned in oxygen to yield 0.7191Â g of co
olchik [2.2K]
The chemical formula for the compound can be written as,

    CxHyOz 

where x is the number of C atoms, y is the number of H atoms, and z is the number of O atoms. The combustion reaction for this compound is,
   
    CxHyOz + O2 --> CO2 + H2O 

number of moles of C:
     (0.7191 g)(1 mol CO2/44 g of CO2) = 0.0163 mol CO2
 This signifies that 0.0163 mole of C and the mass of carbon in the compound,
        (0.0163 mols C)(12 g C/ 1 mol C) = 0.196 g C

number of moles H:
      (0.1472 g H2O)(1 mol H2O/18 g H2O) = 0.00818 mol H2O

This signifies that there are 0.01635 atoms of H in the compound.
      mass of H in the compound = (0.01635 mols H)(1 g of H) = 0.01635 g H

Mass of oxygen in the compound,
   0.3870 - (0.196 g C + 0.01635 g H) = 0.1746 g

Moles O in the compound = (0.1746 g O)(1 mol O/16 g O) = 0.0109 mols O

The formula of the compound is,
      C0.0163H0.01635O0.0109

Dividing the numbers by the least number,
    C3/2H3/2O

The empirical formula of the compound is therefore,
    <em>  C₃H₃O₂</em>
5 0
2 years ago
How is the separation of dna like a zipper
Sedbober [7]

The two strands must be separated like the two sides of a zipper, by breaking the weak hydrogen bonds that link the paired bases.

<u>Explanation:</u>

  • A double helix structure formed by two polypeptide chains is separated like the two sides of a zipper. A zipper is formed by breaking the weak hydrogen bonds that link the paired bases. During replication, an enzyme "Helicase" travels down the DNA and splits the chain and it forms 2 separate strands.
  • The two DNA strand which has the same sequence must be separated like the two sides of a zipper by breaking weak hydrogen bases. During base pair-rule, the strand are unzipped and each strands is copied.

     

3 0
2 years ago
Green light has a frequency of about 6.00×1014s−1. What is the energy of a photon of green light?
Sindrei [870]

3.98 x 10⁻¹⁹ Joule

<h3>Further explanation</h3>

<u>Given:</u>

The green light has a frequency of about 6.00 x 10¹⁴ s⁻¹.

<u>Question:</u>

The energy of a photon of green light (in joules).

<u>The Process:</u>

The energy of a photon is given by \boxed{\boxed{ \ E = hf \ }}

  • E = energy in joules
  • h = Planck's constant 6.63 x 10⁻³⁴ Js
  • f = frequency of light in Hz (sometimes the symbol f is written as v)

Let us find out the energy of the green light emitted per photon.

\boxed{ \ E = (6.63 \times 10^{-34})(6.00 \times 10^{14}) \ }

Thus, we get a result of \boxed{\boxed{ \ E = 3.98 \times 10^{-19} \ J \ }}

- - - - - - - - - -

Notes

  • When an electron moves between energy levels it must emit or absorb energy.  
  • The energy emitted or absorbed corresponds to the difference between the two allowed energy states, i.e., as packets of light called photons.  
  • A higher energy photon corresponds to a higher frequency (shorter wavelength) of light.
<h3>Learn more</h3>
  1. The energy of the orange light emitted per photon brainly.com/question/2485282#
  2. Determine the density of our sun at the end of its lifetime brainly.com/question/5189537  
  3. Find out the kinetic energy of the emitted electrons when metal is exposed to UV rays brainly.com/question/5416146  

Keywords: green light, frequency, the energy, a photon, Planck's constant, electrons, emitted, wavelength, joules

7 0
2 years ago
A 92.8 gram sample of CuSO4•5H2O.(copper sulfate pentahydrate) is heated until water is released. How many grams of water were r
Ivan

Mass of water released =

92.8 g CuSO_{4}.5H_{2}O×\frac{5 * 18 g H_{2}O}{249.68 g CuSO_{4}.5H_{2}O}

= 33.45 g H_{2}O

7 0
1 year ago
Read 2 more answers
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