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Anestetic [448]
2 years ago
3

In a movie theatre, the number of seats in a row is 8 greater than the total number of rows. How many rows are in the movie thea

tre, if the total number of seats in the theatre is 884?
Mathematics
2 answers:
zheka24 [161]2 years ago
8 0

Answer:

no of seats rows will be equal to 26

Step-by-step explanation:

Let as assume number of   rows be 'R'

number of seats in the rows be 'R+8'

number of seats can be taken as the number of columns in theater

total no of seats will be

                     =  number of column ×  number of rows

             884  =  (R+8) × R

             R² + 8 R - 884 = 0

             R² + 34 R - 26 R- 884 = 0

             (R +34) - 26 (R +34) = 0

              (R +34)(R-26) = 0

                 R = 26,-34

hence, no of seats rows will be equal to 26 and column will be equal to 34.

             

poizon [28]2 years ago
3 0
(R + 8) represents the number of seats.

Total seats = R (R + 8) 

R(R + 8) = 884 

R^2 + 8R - 884 = 0 

(R - 26) (R + 34) = 0 

R = 26

so that means there are 26 rows in the movie theater.
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Answer:

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Step-by-step explanation:

Given intervals are,

(i) [a,a] (ii) [a,a) (iii) (a,a] (iv) (a,a) (v) (a,b) where a>b (vi)  [a,b] where a>b.

To show all its elements,

(i) [a,a]

Imply the set including aa from left as well as right side.

Its elements are of the form.

\{[a,a] : a\in \mathbb R\}=\{[0,0],[1, 1],[-1,-1],[2,2],[-2,-2],[3,3],[-3,-3],........\}

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(ii) [a,a)

This means given interval containing a by left and exclude a by right.

Its elements are of the form.

[ 1, 1),[-1,-1),[2,2),[-2,-2),[3,3),[-3,-3),........

Since there is a singleton element a of real numbers withis the set, this set is empty.

Because there is no increment so if a\in \mathbb R then the set  [a,a) represents singleton sets, and singleton sets are empty so is [a.a).

(iii) (a,a]

It means the interval not taking a by left and include a by right.

Its elements are of the form.

( 1, 1],(-1,-1],(2,2],(-2,-2],(3,3],(-3,-3],........

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(iv) (a,a)

Means given set excluding a by left as well as right.

Since there is a singleton element a of real numbers, this set is empty.

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(v) (a,b) where a>b.

Which indicate the interval containing a, b such that increment of x is always greater than increment of y which not take x and y by any side of the interval.

That is the graph is bounded by value of a and it contains elements like it we fixed a=5 then,

(a,b)=\{(5,0),(5,1),(5,2).....\} e.t.c

So this set is connected and we know singletons are connected in \mathbb R. Hence given set is empty.

(vi) [a,b] where a\leq b.

Which indicate the interval containing a, b such that increment of x is always greater than increment of y which include both x and y.

That is the graph is bounded by value of a and it contains elements like it we fixed a=5 then,

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So this set is connected and we know singletons are connected in \mathbb R. Hence given set is empty.

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