Question

36x2 + 49y2 = 1,764 The foci are located at: (-√13, 0) and (√13,0) (0, -√13) and (0,√13) (-1, 0) and (1, 0)

Answer 1

Answer:

The correct option is 1.

Step-by-step explanation:

The given function is

$36x^2+49y^2=1764$

Divide both sides by 1764,

$\frac{x^2}{49}+\frac{y^2}{36}=1$         .... (1)

The standard form of ellipse is

$\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$         .... (2)

The focus of this equation is $(\pm c,0)$.

where, $c^2=a^2-b^2$

On comparing (1) and (2), we get

$a^2=49, b^2=36$

$c^2=a^2-b^2$

$c^2=49-36$

$c^2=13$

$c=\pm\sqrt{13}$

Therefore the foci of the given ellipse are  (-√13, 0) and (√13,0). Option 1 is correct.