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2 years ago

Rearrange the equation to isolate A. H=K+log(A/C)

Mathematics

2 answers:

Maslowich2 years ago

4 0

H = K + log ( A/C )
log ( A/C ) = H - K
$\frac{A}{C}= 10^{H-K}$
$A = C*10 ^{H-K}$

Xelga [282]2 years ago

3 0

Answer:

$A=C(10)^{H-K}$

Step-by-step explanation:

The given equation is

$H=K+\log(\frac{A}{C}$

Subtract K to both sides of the equation

$H-K=\log(\frac{A}{C}$

Now, use the property, $x=\log y\Rightarrow y=10^x$

$10^{H-K}=(\frac{A}{C}$

Multiply both sides by C to isolate A

$A=C(10)^{H-K}$

The value of A is

$A=C(10)^{H-K}$

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