answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Jobisdone [24]
2 years ago
12

You are holding a block of wood with dimensions 3 cm 6 cm 9 cm on the palm of your hand. Which side must be touching your hand f

or you to experience the greatest force?
A. 3 cm x 6 cm side
B. 6 cm x 9 cm side
C. You will experience the same amount of force on all sides.
D. 9 cm x 3 cm side
Physics
2 answers:
Vlad1618 [11]2 years ago
8 0

Answer:

C. You will experience the same amount of force on all sides.

Explanation:

This is because the only force acting on your hand as a result of the wooden block is gravitational force because no external pressure is exerted on the block.

Gravitational force is a product of mass and acceleration. It has nothing to do with the surface area of the object.

Hence, regardless of the surface of the wooden block resting on your palm, the force remains the same.

Zarrin [17]2 years ago
5 0

C. You will experience the same amount of force on all sides.

The normal force of weight will not differ for different positions of the block.

But the force of pressure applied to the surface of your hand is per unit area. So the side with the smallest area (3 cm x 6 cm) will exert more pressure over a smaller area.

You might be interested in
An elementary particle of mass m completely absorbs a photon, after which its mass is 1.01m. (a) what was the energy of the inco
sdas [7]
A.) We use the famous equation proposed by Albert Einstein written below:

E = Δmc²
where
E is the energy of the photon
Δm is the mass defect, or the difference of the mass before and after the reaction
c is the speed of light equal to 3×10⁸ m/s

Substituting the value:

E = (1.01m - m)*(3×10⁸ m/s) = 0.01mc² = 3×10⁶ Joules

b) The actual energy may be even greater than 3×10⁶ Joules because some of the energy may have been dissipated. Not all of the energy will be absorbed by the photon. Some energy would be dissipated to the surroundings.
8 0
2 years ago
A vessel, divided into two parts by a partition, contains 4 mol of nitrogen gas at 75°C and 30 bar on one side and 2.5 mol of ar
Elena L [17]

Answer:

assume nitrogen is an ideal gas with cv=5R/2

assume argon is an ideal gas with cv=3R/2

n1=4moles

n2=2.5 moles

t1=75°C   <em>in kelvin</em> t1=75+273

t1=348K

T2=130°C  <em>in kelvin</em> t2=130+273

t2=403K

u=пCVΔT

U(N₂)+U(Argon)=0

<em>putting values:</em>

=>4x(5R/2)x(Tfinal-348)=2.5x(3R/2)x(T final-403)

<em>by simplifying:</em>

Tfinal=363K

6 0
2 years ago
A material that has a fracture toughness of 33 MPa.m0.5 is to be made into a large panel that is 2000 mm long by 250 mm wide and
scoray [572]

Answer:

F_{allow} = 208.15kN

Explanation:

The word 'nun' for thickness, I will interpret in international units, that is, mm.

We will begin by defining the intensity factor for the steel through the relationship between the safety factor and the fracture resistance of the panel.

The equation is,

K_{allow} =\frac{K_c}{N}

We know that K_c is 33Mpa*m^{0.5} and our Safety factor is 2,

K_{allow} = \frac{33Mpa*m^{0.5}}{2} = 16.5MPa.m^{0.5}

Now we will need to find the average width of both the crack and the panel, these values are found by multiplying the measured values given by 1/2

<em>For the crack;</em>

\alpha = 0.5*L_c = 0.5*4mm = 2mm

<em>For the panel</em>

\gamma = 0.5*W = 0.5*250mm = 125mm

To find now the goemetry factor we need to use this equation

\beta = \sqrt{sec(\frac{\pi\alpha}{2\gamma})}\\\beta = \sqrt{sec(\frac{2\pi}{2*125mm})}\\\beta = 1

That allow us to determine the allowable nominal stress,

\sigma_{allow} = \frac{K_{allow}}{\beta \sqrt{\pi\alpha}}

\sigma_{allow} = \frac{16.5}{1*\sqrt{2*10^{-3} \pi}}

\sigma_{allow} = 208.15Mpa

So to get the force we need only to apply the equation of Force, where

F_{allow}=\sigma_{allow}*L_c*W

F_{allow} = 208.15*250*4

F_{allow} = 208.15kN

That is the maximum tensile load before a catastrophic failure.

4 0
2 years ago
Suppose a rectangular piece of aluminum has a length D, and its square cross section has the dimensions W XW, where D (W x W) to
Ludmilka [50]

Answer:

R₂ / R₁ = D / L

Explanation:

The resistance of a metal is

        R = ρ L / A

Where ρ is the resistivity of aluminum, L is the length of the resistance and A its cross section

We apply this formal to both configurations

Small face measurements (W W)

The length is

         L = W

Area  

         A = W W = W²

        R₁ = ρ W / W² = ρ / W

Large face measurements (D L)

       Length L = D= 2W

       Area     A = W L

     R₂ = ρ D / WL = ρ 2W / W L = 2 ρ/L

The relationship is

    R₂ / R₁ = 2W²/L

6 0
2 years ago
Shareen performs a skit to model a method of charging. In the skit, a painter shakes her hand and gets paint on her.
Veseljchak [2.6K]

Answer:

It models conduction because the painter represents a charged object and the paint represents electrons that are transferred through contact.

Explanation:

Conduction phenomenon of charging is the process of charging in which two bodies are made in contact with each other so that charges are transferred due to potential difference of two bodies.

here we know that when hands are shake then it will have paint on it. so here due to hand shake the hands are in contact with charge particles and due to contact the electrons are transferred to the hand.

Now here we need to assume that charge of paint must be opposite that of the charge on the hand because only due to opposite charge attraction the paint must be transferred to the hand

SO here correct answer will be

It models conduction because the painter represents a charged object and the paint represents electrons that are transferred through contact.

5 0
2 years ago
Read 2 more answers
Other questions:
  • Rank the tensions in the ropes, t1, t2, and t3, from smallest to largest, when the boxes are in motion and there is no friction
    13·1 answer
  • A toy rocket is shot straight up into the air with an initial speed of 45.0 m/s how long does it takes for the rocket to reach i
    12·2 answers
  • The solar panels used by Mark function because of the photoelectric effect. Light shines on the cells causing electrons to be ej
    5·2 answers
  • While a gymnast is in the air during a leap, which of the following quantities must remain constant for her?A) Angular momentum
    14·1 answer
  • How do some businesses believe VR is affecting their training for employees?
    5·1 answer
  • Two parallel wires carry a current I in the same direction. Midway between these wires is a third wire, also parallel to the oth
    11·2 answers
  • Modern wind turbines generate electricity from wind power. The large, massive blades have a large moment of inertia and carry a
    7·1 answer
  • A jeweler is determining the optical properties of an unknown blue gemstone. She uses an angle of incidence of 62°, and measures
    7·1 answer
  • Brian and Jack decided to investigate which water fountain at school has the coldest water. The two boys take measurements using
    5·1 answer
  • if a net horizontal force of 175 N is applied to a bike whos mass is 43 kg what acceleration is produced
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!