Question

What volume of a 1.00 m stock solution of glucose must be used to make 500.0 ml of a 1.75 ✕ 10–2 m glucose solution in water? (a) 1.75 ml, (b) 8.75 ml, (c) 48.6 ml, (d) 57.1 ml, (e) 28,570 ml?

Answer 1

$\frac{500ml}{} \frac{1l}{1000 \: ml} \frac{1.75x10 ^{ - 2} m}{1 l} \frac{1l}{1m} \: = 8.75ml$

Of Glucose Stock Solution

Answer 2

Answer : The correct option is, (b) 8.75 ml

Solution :

According to the dilution law,

$M_1V_1=M_2V_2$

where,

$M_1$ = molarity of stock solution = 1.00 M

$V_1$ = volume of stock solution = ?

$M_2$ = molarity of glucose solution = $1.75\times 10^{-2}M$

$V_2$ = volume of glucose solution = 500 ml

Now put all the given values in the above law, we get the volume of stock solution.

$(1.00M)\times V_1=(1.75\times 10^{-2}M)\times (500ml)$

$V_1=8.75ml$

Therefore, the volume of 1.00 M stock solution required volume is, 8.75 ml