A charge of -3 means it gained 3 electrons meaning electrons would go from 15 to 18 because protons and electrons are the same and you start with 15.
So your answer is 15 protons, 18 electrons
Answer:
Atorvastatin has two chiral centers. The question doesn't include the box where have to answer but I can show you in an image where are located and their configuration.
Explanation:
The first image shows the chemical structure of atorvastatin and their chiral centers identified as 1 and 2 respectively.
The second image shows the Fischer projections corresponding to every chiral carbon 1 and 2. I wrote R so suggest that there are more carbon atoms forward but not only corresponds to carbon atoms.
You can see that the chiral carbon 1 has R configuration due to the direction from the main substituent to the second follow the clockwise.
The chiral carbon 2 has S configuration due to the direction from the main substituent to the second one go anticlockwise.
According to this formula:
K= A*(e^(-Ea/RT) when we have K =1.35X10^2 & T= 25+273= 298K &R=0.0821
Ea= 85.6 KJ/mol So by subsitution we can get A:
1.35x10^2 = A*(e^(-85.6/0.0821*298))
1.35x10^2 = A * 0.03
A= 4333
by substitution with the new value of T(75+273) = 348K & A to get the new K
∴K= 4333*(e^(-85.6/0.0821*348)
= 2.16 x10^2
Answer:
Carbon=5, hydrogen=12, oxygen=16
Explanation:
Carbon=5, hydrogen=12, oxygen=16
In order to effectively count the number of atoms, we look at the equation closely and take note of the stoichiometric coefficients of each reactant as this influences the number of atoms of that element present.
For instance, oxygen is diatomic and has a stoichiometric coefficient of 8. This implies the there are sixteen atoms of oxygen altogether.
Note that the left hand side refers to the reactants side.
The temperature that would the volume of a gas be 0.550l if it had a volume of 0.432 L at -20.0 c is calculated using the Charles law formula
that is v1/T1=V2/T2
V1=0.550 l
t1=?
T2= -20 c +273 = 253 K
v2= 0.432 l
by making T1 the subject of the formula T1= V1T2/V2
T1= (0.55lL x253)/ 0.432 l = 322.11 K or 322.11-273 = 49.11 C
