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julsineya [31]
2 years ago
10

Which of the following statements best describes the general pattern of composition among the four jovian planets?A) Jupiter is

made mostly of hydrogen, Saturn is made mostly of helium, Uranus is made mostly of hydrogen compounds, and Neptune is made mostly of rock.B) Jupiter is made mostly of hydrogen and helium, while the other three jovian planets are made mostly of hydrogen compounds.C) All four planets have essentially the same composition.D) Jupiter and Saturn have compositions that are fairly different from the compositions of Uranus and Neptune.
Physics
1 answer:
kompoz [17]2 years ago
7 0
<h2>Answer: Jupiter and Saturn have compositions that are fairly different from the compositions of Uranus and Neptune.</h2>

Jovian Planets (means "similar to Jupiter") is the name given to the "gaseous giant" planets of our solar system. Although they share many similarities, they have certain differences.

For example, Jupiter and Saturn are classified as "gas giants", while Uranus and Neptune are "ice giants".

This is also due to the fact that Uranus and Neptune have higher concentrations of <u>methane</u> (hence its bluish color) and some heavier elements such as oxygen, carbon, nitrogen, and sulfur. On the other hand, Jupiter and Saturn tend to be orange-white in appearance due to the mixture of <u>hydrogen</u> that gives off a red aspect.

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Water runs into a fountain, filling all the pipes, at a steady rate of 0.750 m3&gt;s. (a) How fast will it shoot out of a hole 4
kati45 [8]

Answer:

velocity  = 472 m/s

velocity = 52.4 m/s

Explanation:

given data

steady rate = 0.750 m³/s

diameter = 4.50 cm

solution

we use here flow rate formula that is

flow rate = Area × velocity .............1

0.750 = \frac{\pi }{4} × (4.50×10^{-2})²  × velocity

solve it we get

velocity  = 472 m/s

and

when it 3 time diameter

put valuer in equation 1

0.750 = \frac{\pi }{4} × 3 ×  (4.50×10^{-2})²  × velocity

velocity = 52.4 m/s

5 0
2 years ago
A physics professor that doesn’t get easily embarrassed stands at the center of a frictionless turntable with arms outstretched
mr Goodwill [35]
Apply conservation of angular momentum:
L = Iw = const.
L = angular momentum, I = moment of inertia, w = angular velocity, L must stay constant.

L must stay the same before and after the professor brings the dumbbells closer to himself.

His initial angular velocity is 2π radians divided by 2.0 seconds, or π rad/s. His initial moment of inertia is 3.0kg•m^2

His final moment of inertia is 2.2kg•m^2.

Calculate the initial angular velocity:
L = 3.0π

Final angular velocity:
L = 2.2w

Set the initial and final angular momentum equal to each other and solve for the final angular velocity w:

3.0π = 2.2w
w = 1.4π rad/s

The rotational energy is given by:
KE = 0.5Iw^2

Initial rotational energy:
KE = 0.5(3.0)(π)^2 = 14.8J

Final rotational energy:
KE = 0.5(2.2)(1.4)^2 = 21.3J

There is an increase in rotational energy. Where did this energy come from? It came from changing the moment of inertia. The professor had to exert a radially inward force to pull in the dumbbells, doing work that increases his rotational energy.
3 0
2 years ago
Read 2 more answers
A person is working on a steel structure while standing on the ground. An accident occurred where 5 A pass through the structure
matrenka [14]

Answer:

35mA

Explanation:

Hello!

To solve this problem we must use the following steps

1. Find the electrical resistance of the metal rod using the following equation

R=\alpha  \frac{l}{a}

WHERE

α=

metal rod resistivity=2x10^-4 Ωm

l=leght=2m

A=  Cross-sectional area

A=\frac{\pi }{4} d^2=\frac{\pi }{4} (0.06)^2=0.00283

solving

R=(2x10^-4)\frac{2}{0.00283} =0.14

2. Now we model the system as a circuit with parallel resistors, where we will call 1 the metal rod and 2 the man(see attached image)

3.we know that the sum of the currents in 1 and 2 must be equal to 5A, by the law of conservation of energy

I1+I2=5

4.as the voltage on both nodes is the same we can use ohm's law in resitance 1 and 2 (V=IR)

V1=V2

(0.14I1)=2000(i2)

solving for i1

I1=14285.7i2

5.Now we use the equation found in step 3

14285.7i2+i2=5

i2=\frac{5}{14285.7+1} =3.5x10^-4A=35mA

6 0
2 years ago
A certain satellite travels in an approximately circular orbit of radius 2.0 × 106 m with a period of 7 h 11 min. Calculate the
kap26 [50]

Answer: Mass of the planet, M= 8.53 x 10^8kg

Explanation:

Given Radius = 2.0 x 106m

Period T = 7h 11m

Using the third law of kepler's equation which states that the square of the orbital period of any planet is proportional to the cube of the semi-major axis of its orbit.

This is represented by the equation

T^2 = ( 4π^2/GM) R^3

Where T is the period in seconds

T = (7h x 60m + 11m)(60 sec)

= 25860 sec

G represents the gravitational constant

= 6.6 x 10^-11 N.m^2/kg^2 and M is the mass of the planet

Making M the subject of the formula,

M = (4π^2/G)*R^3/T^2

M = (4π^2/ 6.6 x10^-11)*(2×106m)^3(25860s)^2

Therefore Mass of the planet, M= 8.53 x 10^8kg

5 0
2 years ago
Notice that in each conversion factor the numerator equals the denominator when units are taken into account. A common error in
navik [9.2K]

Answer:

he factor for the temporal part 1.296 107 s² = h²

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Explanation:

This is a unit conversion exercise.

In the unit conversion, the size of the object is not changed, only the value with respect to which it is measured is changed, for this reason in the conversion the amount that is in parentheses must be worth one.

In this case, it is requested to convert a measure km/h²

Unfortunately, it is not clearly indicated what measure it is, but the most used unit in physics is   m / s² , which is a measure of acceleration. Let's cut this down

the factor for the distance is 1000 m = 1 km

the factor for time is 3600 s = 1 h

let's make the conversion

        m / s² (1km / 1000 m) (3600 s / 1h)²

note that as time is squared the conversion factor is also squared

        m / s² = 12960 km / h²

the factor for the temporal part 1.29 107 s² = h²

6 0
2 years ago
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