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2 years ago

Consider circle O, in which arc XY measures 16π cm. The length of a radius of the circle is 32 cm.

Mathematics

2 answers:

natali 33 [55]2 years ago

8 0

Answer:

Circumference: 64π

Ratio: 1 : 4

Measure of ∠xoy: π/2

Step-by-step explanation:

We are given an arc length of 16π. Since it's in terms of pi, we use the formula

S = rФ where r is the radius, and Ф is the measure of the angle in radians (in terms of pi)

We are given S = 16π and r = 32, plug those in and find Ф

16π = 32Ф

16π/32 = Ф

π/2 = Ф

This is the measure of the central angle.

The angle is π/2 radians. There are 2π radians in the circumference, so the circumference is 4 times the arc length created by the central angle. (There are 4 halves in 2) so the ratio of the arc length tothe circumference is 1 : 4

The formula for circumference is C = 2πr, where r is the radius, so we hace

C = 2π(32) = 64π

Vesna [10]2 years ago

4 0

Answer:

1/4

90 degrees

Step-by-step explanation:

just took it! :)

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Show that the three points whose position vectors are 7j+ 10k,-i + 6j+6k and - 4i + +9j + 6k form an isosceles right

Novay_Z [31]

Answer:

AB = √18 , BC=√18 and CA =4

AB²+BC² = CA² and AB=BC

ΔABC isosceles right angled triangle.

Step-by-step explanation:

Given vectors are 7j+ 10k,-i + 6j+6k and - 4i + +9j + 6k

A( 0,7,10), B( -1,6,6) C(-4,9,6)

AB⁻ = OB-OA = -I+6j+6k-(7j+10k) = -I-j-4k

AB = $\sqrt{1+1+16} = \sqrt{18}$

BC = OC-OB = -4i+9j+6k-(-I+6j+6k) = -3i+3j

BC= $\sqrt{9+9} =\sqrt{18}$

CA = OA-OC = 7j+10k - (- 4i + +9j + 6k ) = 4i-2j+4k

CA = $\sqrt{16+4+16} =\sqrt{36} =4$

Since AB²+BC² = CA²

And AB=BC

Therefore it follows that ΔABC is a right angled isosceles triangle

3 0

2 years ago

here is a list of numbers. 7,12,16,20,27,40,56,64. a work out the difference between the two square numbers in the list. b work

poizon [28]

Answer:

see below

Step-by-step explanation:

7,12,16,20,27,40,56,64

The square numbers are 16 = 4^2 and 64 = 8^2

The difference is 64 - 16 =48

The cube numbers are 27 = 3^3 and 64 = 4^3

64 - 27 =37

4 0

2 years ago

Read 2 more answers

Hospital sends an invoice to a patient. The patient schedules a payment plan in which she makes an initial payment of $1,451 the

Korvikt [17]

First month she payed 1451 dollars

Second month she payed 1/3 of that, which is:
1451/3 = 483.66

Third month she payed 1/3 of 483.66 because as text says, every next month she pays 1/3 of previous month payed amount.

483.66/3 = 161.22

Forth month she payed

161.22/3 = 53.74

In total she payed:

$2149.62 - B.

hope this helps :)

3 0

2 years ago

Read 2 more answers

Budget planners in two towns, Alphaville and Betaville, developed models to determine the budget surplus (in dollars) for a year

kramer

Answer:

(a) $-3x^2+150x-10000$

(b) $-\$16,863,760,000$

Step-by-step explanation:

Alphaville's Budget Surplus Model is $-2x^2+ 500x$

Betaville's Budget Surplus Model is $x^2- 100x + 10000.$

We want to determine the expression that shows how much greater Alphaville’s annual budget surplus is than Betaville’s for a particular amount of tax revenue.

To do this, we subtract Betaville's Model from Alphaville's model.

$-2x^2+ 500x-(x^2- 100x + 10000)\\$

Opening the brackets

$-2x^2+ 500x-x^2+100x - 10000\\$

Collect like terms and simplify

$-2x^2-x^2+100x + 500x- 10000\\=-3x^2+150x-10000$

The expression that shows how much greater Alphaville's Budget is:

$-3x^2+150x-10000$

(b) If the tax revenue that year in each town is $75,000

We want to evaluate the expression derived above when the tax revenue that year in each town is $75,000 i.e.at x=75000

$-3x^2+150x-10000\\=-3(75000)^2+150(75000)-10000\\=-\$16,863,760,000$

3 0

2 years ago

Given that a 90% confidence interval for the mean height of all adult males in Idaho measured in inches was [62.532, 76.478]. Us

grigory [225]

Answer:

The confidence interval on this case is given by:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

For this case the confidence interval is given by (62.532, 76.478)[/tex]

And we can calculate the mean with this:

$\bar X = \frac{62.532+76.478}{2}= 69.505$

So then the mean for this case is 69.505

Step-by-step explanation:

Previous concepts

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

$\bar X$ represent the sample mean