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2 years ago

A chemist is using a solution of HNO3 that has a pH of 3.75. What is [H+] for the solution? 1.78 × 10n M n =

Chemistry

2 answers:

pentagon [3]2 years ago

5 0

what is the pOH of the solution? 10.25 is the answer

stepan [7]2 years ago

3 0

Answer:

The concentration of $H^+$ ions in the solution is $1.778\times 10^{-4} M$ .

Explanation:

The pH of the solution is defined as negative logarithm of $H^+$ ion concentration.

$pH=-\log[H^+]$

The pH of the nitric acid solution = 3.75

$3.75=-\log[H^+]$

$[H^+]=Antilog [-3.75]=0.0001778=1.778\times 10^{-4} M$

The concentration of $H^+$ ions in the solution is $1.778\times 10^{-4} M$ .

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Convert 338 L at 63.0 atm to its new volume at standard pressure.

taurus [48]

The new volume at standard pressure of 1 atm is 21294 liters.

Explanation:

Data given:

Initial volume of the gas V1 = 338 liters

initial pressure on the gas P1 = 63 atm

standard pressure as P2 = 1 atm

Final volume at standard pressure V2 =?

The data given shows that Boyle's law equation is to used:

P1V1 = P2V2

rearranging the equation to calculate V2,

V2 = $\frac{P1V1}{P2}$

Putting the values in the equation:

V2 = $\frac{338X63}{1}$

= 21294 L

as the pressure on the gas is reduced to 1 atm the volume of the gas increased incredibly to 21294 litres.

7 0

2 years ago

Calculate the pka of hypochlorous acid. The ph of a 0.015 m solution of hypochlorous acid has a ph of 4.64.

o-na [289]

Answer:

pKa = 7.46

Explanation:

1) Data:

a) Hypochlorous acid = HClO

b) [HClO} = 0.015

c) pH = 4.64

d) pKa = ?

2) Strategy:

With the pH calculate [H₃O⁺], then use the equilibrium equation to calculate the equilibrium constant, Ka, and finally calculate pKa from the definition.

3) Solution:

a) pH

pH = - log [H₃O⁺]

4.64 = - log [H₃O⁺]

$[H_3O^+]= 10^{-4.64} = 2.29.10^{-5}$

b) Equilibrium equation: HClO (aq) ⇄ ClO⁻ (aq) + H₃O⁺ (aq)

c) Equilibrium constant: Ka = [ClO⁻] [H₃O⁺] / [HClO]

d) From the stoichiometry: [CLO⁻] = [H₃O⁺] = 2.29 × 10 ⁻⁵ M

e) By substitution: Ka = (2.29 × 10 ⁻⁵ M)² / 0.015M = 3.50 × 10⁻⁸ M

f) By definition: pKa = - log Ka = - log (3.50 × 10 ⁻⁸) = 7.46

5 0

2 years ago

What is the total number of sp2-hybridized carbon atoms present in the fluorophore used in the experiments

Mandarinka [93]

Answer:

Explanation:

The structure of fluorophore used in the experiments has been drawn in the attachment. And from the drawing counting we can say that there are 9 sp2-hybridized carbon atoms present. Fiuorophores are a fluorescent chemical compound that can re-emit light upon light excitation. Normally used to produce absorbance and emission spectra.