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2 years ago

Why can metallic elements bend, while solid but non-metallic break or crumble?

2 answers:

6 0

Metallic elements are flexible because of its experience for the atoms to roll on top of one added without crushing its metallic bond (This is because it is fascinated with united force, and is the cause why they have higher melting/boiling points); however, a nonmetals form atomic bonds which don't have this property.

lyudmila [28]2 years ago

5 0

Metallic elements can bend because they have the property of being ductile. This means that a solid material stretches under tensile stress. If a material is ductile then it may be stretched into a wire. Further, the material can also be malleable.

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Element M reacts with oxygen to form an oxide with the formula MO. When MO is dissolved in water, the resulting solution is basi

Tpy6a [65]

Answer:

Calcium

Explanation:

Since the element reacts with oxygen to form an oxide with the formula MO, the charge on the element is +2.

Also, since the oxide MO when dissolved in water is basic, the metal is an alkali earth metal.

From the above conditions;

The metal is not arsenic because arsenic is a metalloid has the following oxides As₂O₃ and As₃O₅ and are respectively amphoteric and acidic in nature

The metal is not germanium because is a metalloid and even though germanium oxide has the formula GeO₂, it is amphoteric.

The metal is not chlorine because chlorine is a non-metal

The metal is definitely calcium because calcium oxide has the formula CaO and calcium is an alkaline earth metal.

The metal is not selenium because selenium is anon-meal and its oxide has the formula Se0₂ and is acidic

5 0

2 years ago

Iodine-131 has a half-life of 8.10 days. In how many days will 50 grams of Iodine-131 decay to one-eighth of its original amount

shtirl [24]

What you need to do is find 1/8 of 50
you can just divide 50 by 8 to get 6.25
so now you have to find how many days it will take till there are 6.25 grams of iodine left
every 8.1 days its mass is split in half
so start splitting it in half and every time you do, you add 8.1 days
50/2 =25 8.1
25/2 =12.5 + 8.1
12.5/2= 6.25 +8.1
now you have reached 1/8 of the original amount of Iodine-131
so to find how long it took just add 8.1+8.1+8.1
(this is the same as 8.1x3)
which equals 24.3
it will take 24.3 days for Iodine 131 to decay to 1/8 of its original mass.

(good luck on the regent if thats what your studying for :)

5 0

2 years ago

Read 2 more answers

A system delivers 225 j of heat to the surroundings while delivering 645 j if work calculate the change in the internal Chang

Charra [1.4K]

Heat given out to the surroundings by the system = 225 J

Work done by the system on the surroundings = 645 J

According to the energy conservation, the energy can neither be created nor it can be destroyed, it can transform from one form to another. Hence, the energy which is lost to the surrounding as a work done and heat came from the internal energy of the system.

Hence, the change in the internal energy = - 225 - 645 = - 870 Joules

Negative sign means that the internal energy of the system is decreased by 870 Joules

3 0

2 years ago

Read 2 more answers

Why was Mendeleev's first Periodic Table not accepted my the scientist community when it was published in the late 1800s?

stepan [7]

They found new elements

3 0

1 year ago

Read 2 more answers

If a 1.00 mL sample of the reaction mixture for the equilibrium constant experiment required 32.40 mL of 0.258 M NaOH to titrate

andrey2020 [161]

Answer:

The concentration of acetic acid is 8.36 M

Explanation:

Step 1: Data given

Volume of acetic acid = 1.00 mL = 0.001 L

Volume of NaOH = 32.40 mL = 0.03240 L

Molarity of NaOH = 0.258 M

Step 2: The balanced equation

CH3COOH + NaOH → CH3COONa + H2O

Step 3: Calculate the concentration of the acetic acid

b*Ca*Va = a*Cb*Vb

⇒with b = the coefficient of NaOH = 1

⇒with Ca = the concentration of CH3COOH = TO BE DETERMINED

⇒with Va = the volume of CH3COOH = 1.00 mL = 0.001L

⇒with a = the coefficient of CH3COOH = 1

⇒with Cb = the concentration of NaOH = 0.258 M

⇒with Vb = the volume of NaOH = 32.40 mL = 0.03240 L

Ca * 0.001 L = 0.258 * 0.03240

Ca = 8.36 M

The concentration of acetic acid is 8.36 M

6 0

2 years ago