Explanation:
- A substance will floats if it is having lower density than the density of the liquid in which it is placed.
- A substance will sink if it is having density greater than the density of the liquid in which it is kept.
Density of corn syrup = 
1) Density of gasoline = 
Density of the gasoline is less than the the density of corn syrup which means it will float in corn syrup.
2) Density of water = 
Density of the water is less than the the density of corn syrup which means it will float in corn syrup.
3) Density of honey = 
Density of the gasoline is more than the the density of corn syrup which means it will sink in corn syrup.
4) Density of titanium = 
Density of the titanium is more than the the density of corn syrup which means it will sink in corn syrup.
We use the equation of motion,
Here, S is the height, u is initial velocity and a is acceleration.
Given, 
As acorn falls from tree, therefore we take the value of 
and initial velocity 
.
Substituting these values in equation of motion,
Thus, the time taken by the acorn to fall 20 feet ( 6.096 m ) is 1.12 s.
Answer:
35mA
Explanation:
Hello!
To solve this problem we must use the following steps
1. Find the electrical resistance of the metal rod using the following equation
WHERE
α=
metal rod resistivity=2x10^-4 Ωm
l=leght=2m
A= Cross-sectional area
solving
2. Now we model the system as a circuit with parallel resistors, where we will call 1 the metal rod and 2 the man(see attached image)
3.we know that the sum of the currents in 1 and 2 must be equal to 5A, by the law of conservation of energy
I1+I2=5
4.as the voltage on both nodes is the same we can use ohm's law in resitance 1 and 2 (V=IR)
V1=V2
(0.14I1)=2000(i2)
solving for i1
I1=14285.7i2
5.Now we use the equation found in step 3
14285.7i2+i2=5
Answer:
Explanation:
For this case we know that the initial velocity is given by:
The final velocity on this case is given by:
And we know that it takes 8 seconds to go from 7m/s to 13m/s. We can use the following kinematic formula in order to find the acceleration during the first interval:
If we solve for the acceleration we got:
So for the other traject we assume that the acceleration is constant and the train travels for 16 s. The initial velocity on this case would be 13m/s from the first interval and we can find the final velocity with the following formula:
And if we replace we got:
