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2 years ago

What is the solution set of the quadratic inequality 6x^2+1 greater than or equal to 0?

Mathematics

1 answer:

Ratling [72]2 years ago

7 0

Answer:

Step-by-step explanation:

6x^2 + 1 <= 0

6x^2 <= -1

x^2 <= -1/6

Since we cannot take the square root of a negative number, there is no solution.

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In a science experiment, Shelly has to weigh a compound in grams. The balance in her school measures in milligrams (mg). Shelly

Oksi-84 [34.3K]

We know, 1 g = 1000 mg
so, 1 mg = 1/1000 g
then, 8,450 mg = 1/1000 * 8,450 = 8.450 g

In short, Your Answer would be: 8.450 Grams

Hope this helps!

5 0

2 years ago

Read 2 more answers

If a hospital patient is given 100 milligrams of medicine, which leaves the bloodstream at 14% per hour, how many milligrams of

sergejj [24]

Answer:

<em>24.66 mg</em><em> of medicine will be left.</em>

Step-by-step explanation:

The given exponential equation is,

$A(t)=ie^{rt}$

Where,

A(t) = amount after time t

i = initial amount = 100 mg

r = rate of change = -14% = -0.14 (-ve is taken because the amount is decreasing)

t = time = 10 hours

Putting the values,

$A(t)=100e^{-0.14\times 10}$

$=100e^{-1.4}$

$=24.66\ mg$

3 0

2 years ago

Amir drove from Jerusalem down to the lowest place on Earth, the Dead Sea, descending at a rate of 12 meters per minute. He was

SSSSS [86.1K]

<h2>Answer:</h2>

First of all let's write the slope-intercept form of the equation of a line, which is:

$y=mx+b \\ \\ Where: \\ \\ m: \ slope \\ \\ b: \ y-intercept$

So we just need to find $m \ and \ b$ to solve this problem.

Moreover, this problem tells us that Amir drove from Jerusalem down to the lowest place on Earth, the Dead Sea, descending at a rate of 12 meters per minute. So this rate is the slope of the line, that is:

$m=-12$

Negative slope because Amir is descending. So:

$y=-12x+b$

To find $b$ , we need to use the information that tells us that he was at sea level after 30 minutes of driving, so this can be written as the point $(30,0)$ . Therefore, substituting this point into our equation: