What is the solution set of the quadratic inequality 6x^2+1 greater than or equal to 0?
1 answer:
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First, lets create a equation for our situation. Let 
be the months. We know four our problem that <span>Eliza started her savings account with $100, and each month she deposits $25 into her account. We can use that information to create a model as follows:
</span>
<span>
We want to find the average value of that function </span>from the 2nd month to the 10th month, so its average value in the interval [2,10]. Remember that the formula for finding the average of a function over an interval is:
. So lets replace the values in our formula to find the average of our function:
![\frac{25(10)+100-[25(2)+100]}{10-2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B25%2810%29%2B100-%5B25%282%29%2B100%5D%7D%7B10-2%7D%20)
We can conclude that <span>the average rate of change in Eliza's account from the 2nd month to the 10th month is $25.</span>
</span>
<span>
We want to find the average value of that function </span>from the 2nd month to the 10th month, so its average value in the interval [2,10]. Remember that the formula for finding the average of a function over an interval is:
We can conclude that <span>the average rate of change in Eliza's account from the 2nd month to the 10th month is $25.</span>
She bikes 761.25 miles in all to and from her job in 29 weeks.
Step-by-step explanation:
Distance from her house = 2.625 miles
As this is the distance of one side, she covers same distance for coming back.
Total distance for one day = 2.625 + 2.625 = 5.25 miles
She goes to work for 5 days per week.
29 weeks =
Total distance covered in 29 weeks;
Total distance = Distance for one day * Days in 29 weeks
She bikes 761.25 miles in all to and from her job in 29 weeks.
Keywords: multiplication, distance
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