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2 years ago

Which orbitals form a pi bond

Chemistry

2 answers:

kirill115 [55]2 years ago

4 0

Answer:

Explanation:

Single covalent bonds that form between nuclei are created from the "head-to-head" overlap of orbitals and are called sigma (s) bonds

Svet_ta [14]2 years ago

4 0

Answer: p orbitals

Explanation: pi bonds are formed by side ways overlap of p orbital which leads lower energy state.

If we have p orbital in adjacent carbons then they will undergoes sideways overlap to form pi bond.

For example, Ethene, CH2=CH2 has p orbitals on adjacent carbons which combine sideways and result a double bond (called pi bond)

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A student wants to reclaim the iron from an 18.0-gram sample of iron(III) oxide, which

lilavasa [31]

Answer:

$m_{Fe}=12.6gFe$

Explanation:

Hello,

In this case, since we have grams of iron (III) oxide whose molar mass is 159.69 g/mol are able to compute the produced grams of iron by using its atomic mass that is 55.845 g/mol and their 2:4 molar ratio in the chemical reaction:

$m_{Fe}=18.0gFe_2O_3*\frac{1molFe_2O_3}{159.69gFe_2O_3}*\frac{4molFe_2O_3}{2molFe_2O_3} *\frac{55.845gFe}{1molFe_2O_3} \\\\m_{Fe}=12.6gFe$

Best regards.

3 0

2 years ago

Read 2 more answers

A student measured the mass of some sodium chloride for a lab. the lab called for 6.25 g (the accurate measurement ) , but the s

Yuri [45]

Answer:

The answer is

$\huge 4\%$

Explanation:

The percentage error of a certain measurement can be found by using the formula

$P(\%) = \frac{error}{actual \: \: number} \times 100\% \\$

From the question

actual mass = 6.25 g

error = 6.25 - 6 = 0.25

So we have

$p(\%) = \frac{0.25}{6.25} \times 100$

We have the final answer as

Hope this helps you

3 0

2 years ago

Use the conversion factor 1amu=6.66054 x 10^-24 to answer the following questions.. . a) 1.674 x 10^-24 g of neutrons is how man

Wewaii [24]

A.) The conversion factor is 1 amu = $1.66054 ^{-24}g$

To know how many amu in $1.674x10^{-24}g$ grams of neutrons:
$1.674x10^{-24}g ( \frac{x (amu) }{ 1.66054x10^{-24} g)}$

=1.00811 amu

b.) The mass in grams of one lithium ion which has an atomic weight of 6.94 amu.

$6.94 amu (\frac{6.66054 ^{-24} g}{1 amu})$ = $4.62241x10 ^{23} g$

c.) How many amu in 6.492x10^-23g potassium?

$6.492x10^{-23}g ( \frac{x (amu) }{ 1.66054x10^{-24}g })$ = 39.0957 amu

6 0

2 years ago

Read 2 more answers

An unknown element, x, reacts with lithium to form the compound li2x. in other compounds this element also can accommodate up to

aliina [53]

<span>Answer Choices:
A) Ca
B) O
C) Cl
D) s</span>

<span>the formula is Li2X, so the charge on the X anion must be 2-

the ion is X2- elements in group 6A form monatomic ions with a 2- charge. In your list that is O or Po

If the element can accomodate 12 electrons then it can have an expanded octet. Only elements in period 3 and higher can have expanded octets.

So you are looking for a group 6A element in period 3 or higher.
cA would not intereact with LI BECAUSE ITS A METAL The only element that fits the bill is D) S</span>

7 0

2 years ago

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Freon-11, CCl3F has been commonly used in air conditioners. It has a molar mass of 137.35 g/mol and its enthalpy of vaporization

PilotLPTM [1.2K]

Answer:

180.56 Kilo joules of energy is removed in the form of heat when 1.00 kg of freon-11 is evaporated.

Explanation:

Molar mass of freon-11 = 137.35 g/mol

Enthalpy of vaporization of freon-11= $\Delta H_{vap}=24.8 kJ/mol$