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kkurt [141]
2 years ago
9

Write a balanced half-reaction for the reduction of gaseous nitrogen (N2) to aqueous hydrazine (N2H4) in basic aqueous solution.

Chemistry
1 answer:
weqwewe [10]2 years ago
5 0

Answer:

N₂(g) + 4H⁺(aq) + 4e⁻ → N₂H₄(aq)

Explanation:

The half reaction for the reaction for the reduction of gaseous nitrogen to aqueous hydrazine is;

N₂(g) → N₂H₄(aq)

The balancing the atoms in the half reaction. Hydrogen atom is balanced by adding hydrogen ions (H⁺)

We have;

N₂(g) + 4H⁺(aq) → N₂H₄(aq)

Then we balance the charge on both sides by adding electrons where the positive charge is greater;

we have;

N₂(g) + 4H⁺(aq) + 4e⁻ → N₂H₄(aq)

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A curium-245 nucleus is hit with a neutron and changes as shown by the equation. Complete the equation by filling in the missing
Lera25 [3.4K]

Try this option:

^{245}_{96}Cm+^1_0n=^{103}_{42}Mo+^{245+1-103-3*1}_{96+0-42-3*0}(X)+3^1_0n;

^{245}_{96}Cm+^1_0n=> ^{103}_{42}Mo+^{140}_{54}(X)+3^1_0n;

^{245}_{96}Cm+^1_0n=> ^{103}_{42}Mo+^{140}_{54}Xe+3^1_0n;

Answer:

^{140}_{54}Xe

8 0
2 years ago
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How many grams are in 2.5 pound sample
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About 2,500 grams Ans balkfdoaks; 
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2 years ago
Write the balanced chemical equation for the reaction shown.
son4ous [18]

Explanation:

        Carbon                  black sphere

        Nitrogen                blue sphere

        Chlorine                green sphere

        Hydrogen              white sphere

 Reactants:

  three molecules that contain one black sphere and four white spheres

           3CH₄

three molecules that contain two blue spheres and four green spheres:

           3N₂Cl₄

Products:

 three molecules that contain one black sphere and four green spheres:

           3CCl₄

 three molecules that contain two blue spheres:

            3N₂

   six molecules that contain two white spheres

            6H₂

The reaction proper:

                    3CH₄ +      3N₂Cl₄  →   3CCl₄ + 3N₂ + 6H₂

Learn more:

Chemical reactions  brainly.com/question/4216541

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7 0
2 years ago
When iron pyrite (FeS2) is heated in air, the process known as "roasting" forms sulfur dioxide and iron(III) oxide. When the equ
Ronch [10]

Answer:

The coefficient of O2 is 11

Explanation:

Step 1:

The equation for the reaction:

FeS2 + O2 → SO2 + Fe2O3

Step 2:

Balancing the equation. The equation can be balance as follow:

FeS2 + O2 → SO2 + Fe2O3

There are 2 atoms of Fe on the right side and 1 atom on the left. It can be balance by putting 2 in front of FeS2 as shown below:

2FeS2 + O2 → SO2 + Fe2O3

There are 4 atoms of S on the left side and 1 atom on the right side. It can be balance by putting 4 in front of SO2 as shown below:

2FeS2 + O2 → 4SO2 + Fe2O3

Now, there are a total of 11 atoms of O on the right side and 2 atoms on the left side. It can be balance by putting 11/2 in front of O2 as shown below:

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Multiply through by 2 to clear the fraction as shown below:

4FeS2 + 11O2 → 8SO2 + 2Fe2O3

Now the equation is balanced.

The coefficient of O2 is 11

8 0
2 years ago
Given the connection between Aw and K (Aw=2k) could you use the ideal gas law and derive the Boltzmann constant. Water freezes a
Elena L [17]

Answer:

Explanation:

The relation between new scale and absolute temperature scale is given as follows

Aw = 2 K

for K = 273.15 ( freezing point of water at absolute scale )

Aw = 2 x 273.15 = 546.3 K

So each division of new scale is half the each division of absolute scale

each division of new scale is small .

The value of R  = 8.314 J per mole per K

Here per K is equivalent to 2Aw

So the vale of R in new scale = 8.314/2 J per mole per Aw

=  4.157 J per mole per Aw

k = R / N

= 4.157 / 6.02 x 10²³

= .69 x 10⁻²³

= 6.9 x 10⁻²⁴ J per molecule per Aw .

7 0
2 years ago
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