Square KITE has vertices (-4, 0), (0, 4), (4, 0), and (0, -4), respectively. Name the square's diagonals and find their point of
intersection.
Complete your work in the space provided or upload a file that can display math symbols if your work requires it.
Complete your work in the space provided or upload a file that can display math symbols if your work requires it.
1 answer:
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Answer:
Option 3 is correct.
The data do not provide sufficient evidence to reject H0; thus, we cannot conclude that the mean point spread of home games is higher than that of away games.
Step-by-step explanation:
Before anything else, we first give the null and alternative hypothesis for this question.
Null hypothesis would be that there isn't significant evidence to conclude that the mean point spread of home games is higher than that of away games.
H0: µ1 = µ2
And the alternative hypothesis would be that there is significant evidence to conclude that the mean point spread of home games is higher than that of away games.
Ha: μ1 > μ2
The data from the output of the analysis of the hypothesis test is missing from the question. It was obtained online and is attached to this solution of the question.
The table consists of the difference, the sample mean, the standard error of the mean, degree of freedom, the test statistic and most importantly, the p-value. It is the p-value that absolutely gives us the concluding statement of the hypothesis testing.
When the significance level for a test isn't provided, the convention is usually to use 5% significance.
Interpretation of p-value
When the (p-value > significance level), we fail to reject the null hypothesis and when the (p-value < significance level), we reject the null hypothesis and accept the alternative hypothesis.
So, for this question, significance level = 0.05
p-value = 0.4351
0.4351 > 0.05
Hence,
p-value > significance level
This means that we fail to reject the null hypothesis & say that 'The data do not provide sufficient evidence to reject H0; thus, we cannot conclude that the mean point spread of home games is higher than that of away games'.
Hope this Helps!!!
<h2>Answer</h2>
0.43
<h2>Explanation</h2>Remember that
Since the problem is telling us "Among tenth graders", we must focus on the 10th graders row only. From the row, we can infer that the frequency is the number of 10th graders who prefer going to sporting events, so . Now, the sum of all frequencies will be the sum of all the 10th graders, so
. Let's replace the values:
And rounded to the nearest hundredth: