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Blizzard [7]
2 years ago
10

One brand of vinegar has a pH of 4.5. Another brand has a pH of 5.0. The equation for the pH of a substance is pH = –log[H+], wh

ere H+ is the concentration of hydrogen ions. What is the approximate difference in the concentration of hydrogen ions between the two brands of vinegar?
Mathematics
2 answers:
likoan [24]2 years ago
6 0

Answer:

The vinegar with pH 4.5 has 2.2*10^-5 more hydrogen ions than the vinegar with pH 5.0.

Explanation:

To identify the difference, we must first find the H+ of both. We can do this by using the equation [H+]=10^-pH. After we do that we know that the vinegar with a pH of 5.0 has [H+]=1.0*10^-5 and the vinegar with a pH of 4.5 has [H+]=3.2*10^-5. The difference is found by subtraction.

(3.2*10^-5)-(1.0*10^-5)=2.2*10^-5

kiruha [24]2 years ago
4 0

Answer:

2.16 * (10^-5).

Step-by-step explanation:

5 = -log H+

5 = log (1 / H+)

1/ H+ = 10^5

H+ = 10^-5

In a similar fashion  the other brand has H+ of 10^-4.5.

So the difference in hydrogen ion concentration =  10^(-4.5) - 10^(-5)

= 2.16 * (10^-5).

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Answer:

Step-by-step explanation:

Given that a group of students estimated the length of one minute without reference to a watch or​ clock, and the times​ (seconds) are listed below.

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70 79 38 63 44 23 62 61 67 50 61 70 94 87 65

Mean = 62.27Variance =333.35std dev = 18.258std error = 4.714

H0: mu = 60 sec

Ha: mu not equals 60 sec

Mean diff = 2.27

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1 year ago
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2 years ago
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QUICK! 75 POINTS !!Select all that are part of the solution set of csc(x) > 1 and over 0 ≤ x ≤ 2π.
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Answer:

\frac{\pi}{4}

\frac{5\pi}{6}

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The answer uses the unit circle and that sine and cosecant are reciprocals.

The first choice doesn't even fit the criteria that x is between 0 and 2\pi (inclusive of both endpoints) because of the x=\frac{-7\pi}{6}.

Let's check the second choice.

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So we are eliminating 3rd choice now.

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\csc(\frac{7\pi}{6})=-2 \text{ since } \sin(\frac{7\pi}{6})=\frac{-1}{2} which means \csc(\frac{7\pi}{6}) and not greater than 1.

I was looking at the rows as if they were choices.

Let me break up my choices.

So we said x=-\frac{7\pi}{6} doesn't work because it is not included in the inequality 0\le x \le 2\pi.

How about x=0?  This leads to \csc(0) which doesn't exist because \sin(0)=0.

So neither of the first two choices on the first row.

Let's look at the second row again.

We said \frac{\pi}{4} worked but not \frac{\pi}{2}

Let's look at the choices on the third row.

We said \frac{5\pi}{6} worked but not x=\pi

Let's look at at the last choice.

We said it gave something less than 1 so this choice doesn't work.

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