Question

5.90. A force is applied to a block to move it up a 30° incline. The incline is frictionless. If F = 65.0 N and M = 5.00 kg , what is the magnitude of the acceleration of the block? Enter your answer in units of m/s^2m/s 2 , without units, to the nearest hundredth.

Answer 1

Answer:

The acceleration of the block is 6.35 m/s².

Explanation:

It is given that,

A force is applied to a block to move it up a 30° incline. The applied force is, F = 65 N

Mass of the block, m = 5 kg

We need to find the acceleration of the block. From the attached figure, it is clear that.

$F_x=ma_x$

$F\ cos\theta-mg\ sin\theta=ma_x$

$a_x=\dfrac{F\ cos\theta-mg\ sin\theta}{m}$

$a_x=\dfrac{65\ N\ cos(30)-5\ kg\times 9.8\ m/s^2\ sin(30)}{5\ kg}$

$a_x=6.35\ m/s^2$

So, the acceleration of the block is 6.35 m/s². Hence, this is the required solution.