First, calculate for the volume of the cube before each edges are cut.
V = e³
where e is the length of each sides. Substituting the known value,
V = (4/5 cm)³ = 0.512 cm³
Then, calculate for the volume of each of the small cubes cut out from the corners.
V = (1/5 cm)³ = 0.008 cm³
Since there are 8 of these small cube, we multiply the volume by 8.
8V = 8(0.008 cm³) = 0.064 cm³
Then, subtracting the volumes will give us an answer of <em>0.448 cm³</em>
A dilation by a scale factor of 6 will cause the radius to increase by a factor of 6. So

. If we plug this value of r into the formula for the circumference of a circle we get

So basically N = 12r. You haven't given me any original radius, so I can't give you a constant for N, but if you do have that original radius you can just plug that into 12r.
Based on your comment, N = 12 * 9 = 108 inches
(3x³ + 2x² - 5x) - (8x³ - 2x²<span>) =
</span>3x³ + 2x² - 5x - 8x³ + 2x² =
-5x³ + 4x² - 5x
2 shelves will display 2 cars because if 8 shelves display 1 car then there would be missing 4 cars to display and if you display 2 cars in one shelf you will need 2 shelves
B. 12 units because when you add the lengths together you get 12