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2 years ago

The quotient of a number and 12 is no more than 6 \

Mathematics

1 answer:

nasty-shy [4]2 years ago

4 0

Let the number be x, then
x/12 <= 6
x <= 6 x 12
x <= 72

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Carmen draws this area model to help her divide 1,800 by 9. She says the quotient is 20

lisov135 [29]

Answer: the answer is 200

Step-by-step explanation:

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2 years ago

Which expression is equivalent to [4mn/m⁻2n⁻6}⁻2? Assume m and n do not equal zero

leva [86]

The answer would be {(n^5)^2}/{(4*m^3)^2} = { n^{10} }/{16*m^6}

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2 years ago

Read 2 more answers

QUICK QUICK PLZZ! ANSWER QUESTION ONLY 1 MINUTE ONLY WITH SOLUTION! THE YOU WILL BE THE BRAINLIEST

nekit [7.7K]

Answer:

576.2

Step-by-step explanation:

The formula for the area of a triangle is $\frac{bh}{2}$ . Since this square pyramid is essentially four triangles with base length 21.5 feet and height 13.4 feet, we can calculate the area that they take up with the formula $4\cdot \frac{13.4\cdot 21.5}{2}=576.2$ square feet. Hope this helps!

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2 years ago

It takes 6 cubic inches of colored sand to fill a plastic cone. How many cubic inches will it take to fill a plastic cylinder wi

frosja888 [35]

The volume of a cone is equal to
Volume = pi * r^2 * h / 3

The volume of a cylinder is equal to
Volume = pi * r^2 * h

The cone is filled with 6 cubic inches colored sand.
As you observed, the volume of the cone is 1 / 3 of the volume of the cylinder.

Cone = Cylinder / 3
6 = Cylinder / 3
Cylinder = 18

So the answer is A. 18.

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2 years ago

The national average for mathematics SATs in 2011 was 514 and the standard deviation was approximately 40. a) Within what bounda

blondinia [14]

Answer:

$0.75 = 1-\frac{1}{k^2}$

If we solve for k we can do this:

$\frac{1}{k^2}= 1-0.75=0.25$

$\frac{1}{0.25}= k^2$

$k^2 =4$

$k =\pm 2$

So then we have at last 75% of the data withitn two deviations from the mean so the limits are:

$Lower = \mu -2\sigma = 514- 2*40=434$

$Upper = \mu +2\sigma = 514 + 2*40=594$

Step-by-step explanation:

We don't know the distribution for the scores. But we know the following properties:

$\mu = 514 , \sigma =40$

For this case we can use the Chebysev theorem who states that "At least $1 -\frac{1}{k^2}$ of the values lies between $\mu -k\sigma$ and $\mu +k\sigma$ "