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Leokris [45]
2 years ago
10

The graph represents velocity vs. time for Carla.

Physics
2 answers:
Andrews [41]2 years ago
4 0

Answer:

It's C, I found it on quizlet and got it right. Hope you get it right :)

Kruka [31]2 years ago
4 0

Answer: C

Explanation:

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In at least 150 words, discuss how Chang's use of personification, metaphor, or connotation express one his themes in "Garden of
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2 years ago
What can happen to an electron when sunlight hits it? select all that apply. select all that apply. it can drop down to a lower
vlabodo [156]
There are two possible answers:
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In fact, sunlight consists of photons. When sunlight hits an electron, the electron can absorbs a photon, so it gains energy: as a result, the electron can move to a higher electron shell, which corresponds to a high energy level in the atom, if the energy given by the photon is at least equal to the energy difference between the two levels. However, if the photon energy is not large enough, the electron will stay in the same shell.</span>
4 0
2 years ago
Read 2 more answers
A constant torque of 200Nm turns a wheel about its centre. The moment of inertia of it about the axis is 100kgm^s . Find the kin
AleksAgata [21]
It would turn  160 degrees after twenty truns

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3 0
2 years ago
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A car travels forward with constant velocity. It goes over a small stone, which gets stuck in the groove of a tire. The initial
puteri [66]

Answer:

A) vertically upward

Explanation:

Since the tyre is rotating with uniform angular speed and moving with constant linear speed

So as soon as a small stone is stuck into the groove of the tyre the speed of the stone is same as that of the tyre

so now we can say that stone will start revolving with the tyre of the car at constant angular speed and moving with uniform speed also

so here just after that the tangential acceleration of the stone must be zero while radial acceleration must be towards the center of the tyre given as

a_c = \omega^2 R

so we will have direction of net acceleration is towards its center so correct answer will be

A) vertically upward

7 0
2 years ago
refrigerant 134a enters a compressor operating at steady state as saturated vapor at 0.12 MPa and exits at 1.2 MPa and 70 C at a
Afina-wow [57]

Answer:

the power input to the compressor is 7.19Kw

Explanation:

Hello!

To solve this problem follow the steps below.

1. We will call 1 the refrigerant state at the compressor inlet and 2 at the outlet.

2. We use thermodynamic tables to determine enthalpies in states 1 and 2.

(note: Through laboratory tests, thermodynamic tables were developed, these allow to know all the thermodynamic properties of a substance (entropy, enthalpy, pressure, specific volume, internal energy etc ..)  

through prior knowledge of two other properties such as pressure and temperature.  )

h1[quality=1, P=0.12Mpa)=237KJ/Kg

h2(P=1.2Mpa, t=70C)=300.6KJ/kg

3. uses the first law of thermodynamics in the compressor that states that the energy that enters a system is the same that must come out

Q=heat=0.32kJ/s

W=power input to the compressor

m=mass flow=0.108kg/S

m(h1)+W=Q+m(h2)

solving for W

W=Q+m(h2-h1)

W=0.32+0.108(300.6-237)=7.19Kw

the power input to the compressor is 7.19Kw

7 0
2 years ago
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