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Alik [6]
2 years ago
13

A caterers fee is based on the number of meals she provides how much is the price per meal if the total fee is $1,088 for 64 mea

ls
Mathematics
2 answers:
svlad2 [7]2 years ago
7 0
<h2>Answer:</h2>

The price per meal provided by her is:

                         $ 17

<h2>Step-by-step explanation:</h2>

It is given that:

The fees of caterer is dependent on the number of meals she provides.

Also, it is given that:

The total fees is: $ 1088

and the number of meals provided by her is: 64

Now, we are asked to find the unit rate of the meal i.e. we have to find the cost of 1 meal.

We know that the cost of 1 meal is calculated as the ratio of the total fees to the number of meals provided by her.

i.e.

\text{Cost\ of\ one\ meal}=\dfrac{1088}{64}\\\\i.e.\\\\\text{Cost\ of\ one\ meal}=\$\ 17

blsea [12.9K]2 years ago
3 0
1,088 / 64 = 17

The caterers fee is $17 per meal
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Answer:the answer is D)  5(30 - 5) + 40; 165 stars

Step-by-step explanation:because you multiply the number of levels between Level 30 and Level 5 by 5 stars per level. Add the number of stars needed in Level 5.

5(30 - 5) + 40

5(25) + 40

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2 years ago
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PLEASE HELP!
Bond [772]

Let x be the number of Standard Specials sold last Monday and y be the number of Deluxe specials sold last Monday.  

The Standard special sells for $2, then x Standard Specials cost $2x.

The Deluxe special sells for $4.50, then y  Deluxe specials cost $4.50y.

1. Last Monday, PB&P sold at least $200 worth of Standard and Deluxe peanut butter and pickle sandwich specials. This means that

2x+4.50y≥200.

2.  When all related business expenses are included, the Standard special costs $0.50 to prepare, then x Standard Specials cost $0.50x.

When all related business expenses are included, the Deluxe special costs $1.25 to prepare, then y Deluxe specials cost $1.25y.

Expenses were no more than $100, then

0.50x+1.25y≤100.

3. At least 30 Standard special were sold, then x≥30.

4. Graph all these inequalities (see attached diagram). As you can see only point (60,70) doesn't belong to needed region.

Answer: all points except point (60,70)

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2 years ago
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Triangle $ABC$ has altitudes $\overline{AD},$ $\overline{BE},$ and $\overline{CF}.$ If $AD = 12,$ $BE = 14,$ and $CF$ is a posit
Shalnov [3]

Answer:

<u>CF = 7</u>

Step-by-step explanation:

Given: Δ ABC

Altitudes ⇒ AD = 12 , BE = 14  and  CF = ?

The area of the triangle = 0.5 AD * BC ⇒ (1)

OR area                          = 0.5 BE * AC  ⇒ (2)

OR area                          = 0.5 CF * AB  ⇒ (3)

By equating (1) and (3)

∴ 0.5 CF * AB = 0.5 AD * BC

∴ CF = \frac{AD*BC}{AB} =\frac{12BC}{AB} ⇒ (4)

By equating (1) and (2)

0.5 BE * AC = 0.5 AD * BC

∴ \frac{AC}{BC} = \frac{AD}{BE} =\frac{12}{14} =\frac{6}{7} (5)

We should know that about the relation between the sides of the triangle:

The sum of two sides will be greater than the third side

So, AB < BC + AC    ⇒ divide both sides by BC

∴ \frac{AB}{BC} < 1+\frac{AC}{BC}

By substitution from (5) with AC/BC

∴ \frac{AB}{BC}

∴ \frac{AB}{BC}

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By substitution from (6) at (4)

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2 years ago
World wind energy generating1 capacity, W , was 371 gigawatts by the end of 2014 and has been increasing at a continuous rate of
Sunny_sXe [5.5K]

Answer:

a) W(t) = 371(1.168)^{t}

b) Wind capacity will pass 600 gigawatts during the year 2018

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The world wind energy generating capacity can be modeled by the following function

W(t) = W(0)(1+r)^{t}

In which W(t) is the wind energy generating capacity in t years after 2014, W(0) is the capacity in 2014 and r is the growth rate, as a decimal.

371 gigawatts by the end of 2014 and has been increasing at a continuous rate of approximately 16.8%.

This means that

W(0) = 371, r = 0.168

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W(t) = W(0)(1+r)^{t}

W(t) = 371(1+0.168)^{t}

W(t) = 371(1.168)^{t}

(b) When is wind capacity predicted to pass 600 gigawatts? Wind capacity will pass 600 gigawatts during the year?

This is t years after the end of 2014, in which t found when W(t) = 600. So

W(t) = 371(1.168)^{t}

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(1.168)^{t} = \frac{600}{371}

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We have that:

\log{a^{t}} = t\log{a}

So we apply log to both sides of the equality

\log{(1.168)^{t}} = \log{1.61725}

t\log{1.168} = 0.2088

0.0674t = 0.2088

t = \frac{0.2088}{0.0674}

t = 3.1

It will happen 3.1 years after the end of 2014, so during the year of 2018.

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2 years ago
A study of consumer smoking habits includes 177 people in the 18-22 age bracket ( 48 of whom smoke), 146 people in the 23-30 age
svp [43]

Answer:

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Step-by-step explanation:

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Age 18-22 has 177 people. 48 of whom smoke.

People who does not smoke =(177-48) + (146-31) +(81-28)

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People with age (18-22) who does not smoke = 129

P(18-22 or does not smoke) = (177+297-129)/(177+146+81)

P(18-22 or does not smoke) = 345/404

P(18-22 or does not smoke) = 0.854

Thus the probability of getting someone who is age 18-22 or does not smoke is 0.854 ....

3 0
2 years ago
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