Question

A hockey goalie is standing on ice. Another player fires a puck (m = 0.170 kg) at the goalie with a velocity of +44.6 m/s. (a) If the goalie catches the puck with his glove in a time of 5.02 x 10-3 s, what is the magnitude of the average force exerted on the goalie by the puck? (b) Instead of catching the puck, the goalie slaps it with his stick and returns the puck straight back to the player with a velocity of -44.6 m/s. The puck and stick are in contact for a time of 5.02 x 10-3 s. Now, what is the magnitude of the average force exerted on the goalie by the puck? Verify that your answers to parts (a) and (b) are consistent with the conclusion of Conceptual Example 3.

Answer 1

Answer:

Explanation:

calculate the momentum before the puck hits the goalie: momentum = mass*velocity  

p = 0.17*54.9  

p = 9.333 kg.m/s  

Because the final momentum is zero, the change in momentum is also 9.333, which is also called impulse.  

Apply impulse = Force*time  

9.333 = 3.62*10^-3*F  

F = 2578.17679558  

Therefore the average force exerted is 2578N  

 

First few instances I performed goalie, I wore a participant helmet with cage + neck protector. (Cooper HH 3000 if it concerns) in case you could purchase some extra padding and function it placed into the goalie helmet. Use of a "doo-rag" (kinda feels like a yamulkha) will soak up a number of the surplus room as properly. the burden is greater on the grounds which you at the instant are not used to it. yet in the top, it is your protection on the line.