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2 years ago

Which of the following forms of radiation can penetrate up to a 2-cm layer of skin tissue?

Physics

2 answers:

Dmitry_Shevchenko [17]2 years ago

4 0

Answer:

d). X-rays

Explanation:

X -rays are also called photons. They are a packet of electro magnetic radiation. X rays originate from the shell of the electron. X rays are highly penetrating, and have a shorter wavelength than alpha particles and the beta particles. They are similar to the gamma rays which are also has a high penetrating power and easily pass through the human body.

Thus X rays can penetrate a skin tissue upto 2 cm thickness.

Paraphin [41]2 years ago

3 0

Answer:

Explanation:

Alpha and beta particles are actually particulate radiation. X and Gamma rays are electromagnetic radiation.

Among the options, beta particles and X-Rays are the ones that can penetrate skin, but only X-Rays can go 2 cm deeper.

Actually, beta particles or beta radiation in the tissue can penetrate just a few milimeters, but X-Rays can penetrate many centimeters. That's why X-Rays are used to examine bones, it's too deep to use beta radiation.

Therefore, the right answer is D.

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A 14000N car traveling at 25m/s rounds a curve of radius 200m. Find the following: a. The centripetal acceleration of the car.

tamaranim1 [39]

Answer:

Explanation:

Given

Weight of car $W=14,000\ N$

mass of car $m=\frac{14,000}{9.8}=1428.57\ N$

velocity of car $v=25\ m/s$

radius $r=200\ m$

(a)Centripetal acceleration is given by

$a_c=\frac{v^2}{r}$

$a_c=\frac{25^2}{200}$

$a_c=3.125\ m$

(b)Force that provide centripetal acceleration

$F=F_c=\frac{mv^2}{r}$

$F=\frac{1428.57\times 25^2}{200}$

$F=4464.285\ N$

(c)Friction force between car and tires is given by

$=\mu N$

where $\mu$ =coefficient of static friction

N=normal reaction

Centripetal force will balance the friction force

$F_c=F_r$

$4464.285=\mu \times 1428.57\times 9.8$

$\mu =0.318$

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2 years ago

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It has been proposed that extending a long conducting wire from a spacecraft (a "tether") could be used for a variety of applica

denis23 [38]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The angle between shuttle's velocity and the Earth's field is $\theta = 24.2^o$

Explanation:

From the question we are told that

The length of eire let out is $L = 250 \ m$

The emf generated is $\epsilon = 40 V$

The earth magnetic field is $B = 5.0 *10^{-5} T$

The speed of the shuttle and tether is $v = 7.80 * 10^3 \ m/s$

The emf generated is mathematically represented as

$\epsilon = L\ v\ B\ sin \ \theta$

making $\theta$ the subject of the formula

$\theta = sin ^{-1}[ \frac{\epsilon}{L * B *v} ]$

substituting values

$\theta = sin ^{-1}[ \frac{40}{250 * (5*10^{-5}) *(7.80 *10^{3})} ]$

$\theta = 24.2^o$

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2 years ago

Find the time t1 it takes to accelerate the flywheel to ω1 if the angular acceleration is α. express your answer in terms of ω1

VMariaS [17]

T1 = ω1/α.............

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2 years ago

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You are working as an assistant to an air-traffic controller at the local airport, from which small airplanes take off and land.

Alika [10]

Answer:

d = 2021.6 km

Explanation:

We can solve this distance exercise with vectors, the easiest method s to find the components of the position of each plane and then use the Pythagorean theorem to find distance between them

Airplane 1

Height y₁ = 800m

Angle θ = 25°

cos 25 = x / r

sin 25 = z / r

x₁ = r cos 20

z₁ = r sin 25

x₁ = 18 103 cos 25 = 16,314 103 m = 16314 m

z₁ = 18 103 sin 25 = 7,607 103 m= 7607 m

2 plane

Height y₂ = 1100 m

Angle θ = 20°

x₂ = 20 103 cos 25 = 18.126 103 m = 18126 m

z₂ = 20 103 without 25 = 8.452 103 m = 8452 m

The distance between the planes using the Pythagorean Theorem is

d² = (x₂-x₁)² + (y₂-y₁)² + (z₂-z₁)²2

Let's calculate

d² = (18126-16314)² + (1100-800)² + (8452-7607)²

d² = 3,283 106 +9 104 + 7,140 105

d² = (328.3 + 9 + 71.40) 10⁴

d = √(408.7 10⁴)

d = 20,216 10² m

d = 2021.6 km

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