Answer:
1.5s+2.5p<20
Step-by-step explanation:
Multiply by each kilo and then make sure it adds up to less than 20!
In your problem:
p = 18.3% = 0.183
n = 130
The standard error can be calculated by the formula:
SE = √[p · (1 - p) / n]
= √[0.183 · (1 - 0.183) / 130]
= 0.0339
The standard error of the proportion is 0.034.
240,000 is a whole number. Now do the power of ten lol. Use a calculator. Remember don't do it all at once. The powers mean multiplying separate for example: 10×10 equals 100. I hundred times10 equals 1000. That is powered by three because it is multiplying 1030 different times which makes it the power. Simple math these days ha ha
The number of orders in is equal to the number of orders out in month 4 (April). It appears the solution represents the time at which warehouse shipments caught up with order quantities.
_____
For this table to make any sense, we have to assume that the year started with 3 orders in January, and that one order was shipped in January. Then the number of orders was 1 or 2 each month after that, and the number of orders shipped per month was 2 each month after that. That is, the tables represent year-to-date totals of orders in and out.
<em>Alternate Interpretation</em>
If the numbers here are actual orders in and out in each of the listed months, it appears the warehouse is getting better at shipping orders. That is, they are increasing the shipment rate by 2 orders a month each month. They will eventually ship enough to cover the total number of orders in (total of 20 by April), but total shipments through April only amount to 16 orders.
The solution would be like
this for this specific problem:
Since the number of
charter schools is eight less than twice the number of alternative schools,
then it’s:
<span>2x - 8 </span><span>
<span>and then
<span>2x - 8 = 36 </span>
<span>2x = 44 </span>
x = 22 </span></span>
So
there are 22 Alternative Schools in
the county. I am hoping that this answer has satisfied your query
and it will be able to help you in your endeavor, and if you would like, feel
free to ask another question.
