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MakcuM [25]
2 years ago
10

Blood pressure is measured when the blood is pumping (systolic) and when the heart is resting (diastolic). When pressure reading

s are given, the systolic is given first, and healthy blood pressure is around 120 over 80 mm Hg. Recall the density of mercury is 13.6 × 103 kg/m3.
(a) Suppose you have a blood pressure reading of 120 over 83 mm. What is your systolic pressure, in newtons per meter squared?(b) Suppose you have a blood pressure reading of 120 over 83 mm Hg. What is your diastolic pressure, in newtons per meter squared?
Physics
1 answer:
anyanavicka [17]2 years ago
6 0

Answer:

a) P = 15993.6 N/m²

b) P' = 11062.24 N/m²

Explanation:

Given:

Density of the mercury, ρ = 13.6 × 10³ kg/m³

The blood pressure reading is given as 120 over 83 mm

a) Now,

The pressure (P) due to a fluid is given as:

P = ρgh

where, g is the acceleration due to the gravity

h is the pressure head

The systolic pressure head from the blood pressure reading is , h = 120 mm = 0.12 m

substituting the value in the formula for pressure,

we get

P = 13.6 × 10³ × 9.8 × 0.12

or

P = 15993.6 N/m²

b) The systolic pressure head from the blood pressure reading is , h' = 83 mm = 0.083 m

substituting the value in the formula for pressure,

we get

P' = 13.6 × 10³ × 9.8 × 0.083

or

P' = 11062.24 N/m²

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Explanation:

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Formula for change in fringe shift is as follows.

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According to the given data change in fringe is n = 1. The data is Michelson and Morley experiment is as follows.

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Hence, putting the given values into the above formula as follows.

            v = \sqrt{\frac{n \lambda c^{2}}{2l}}

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3 0
1 year ago
A photon is scattered from an initially stationary electron within a metal. How does the frequency of the photon change upon sca
sammy [17]

Answer:

The frequency of the photon decreases upon scattering

Explanation:

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f = c/λ

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f and f' = The frequency of the motion of the photon before and after the scattering

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We have that the frequency, f, is inversely proportional to the wavelength, λ as follows;

f = c/λ

As λ = increases, and c is constant, f decreases, therefore, the frequency of the photon decreases upon scattering.

5 0
2 years ago
A flat metal washer is heated. As the washer's temperature increases, what happens to the hole in the center? A flat metal washe
jenyasd209 [6]

answer;

The hole in the center of the washer will expand

explanation;

<em>A flat metal washer is heated. As the washer's temperature increases, what happens to the hole in the center? A flat metal washer is heated. As the washer's temperature increases, what happens to the hole in the center? The hole in the center will remain the same size. Changes in the hole cannot be determined without know the composition of the metal. The hole in the center of the washer will expand. The hole in the center of the washer will contract.</em>

this is an example of area expansivity.

coefficient of area expansivity is change in area per area per degree rise in temperature

a=dA/(A*dt)

as the temperature rises , there will be volumetric and area expansivity on the body. volume also increases because of the intermolecular forces of attraction between the molecule is now getting apart.

7 0
2 years ago
A man weighing 750 n and a woman weighing 500 n have the same momentum. what is the ratio of the man's kinetic energy km to that
miss Akunina [59]
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Answer:

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7 0
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