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viva [34]
2 years ago
5

Each level of a smartphone app adds more gems for you to match. On level one, there were 13 gems. On level twelve, there were 12

3 gems. When you complete all twelve levels, how many total gems will you have matched? A. 605 B. 660 C. 748 D. 816
Computers and Technology
1 answer:
Sidana [21]2 years ago
5 0
<span>Level : 1,2,3,4,5,6,7,8,9,10,11,12
Gems : 13 to 123
We have to increase from 13 to 123 over a span of 11 levels.
That's an increase of 110 over 11 levels.
110 / 11 = 10
So we go up 10 gems each level Level : 1,2,3,4,5,6,7,8,9,10,11,12
Gems : 13 23 33 43 53 63 73 83 93 103 113 123</span>
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Steven is an advertising executive at a large auto parts company. He uses his google ads recommendations page to help him with s
lana [24]

Answer:

Apply recommendations across the multiple layers of his advertising strategies.

Explanation:

In the given statement, Steven is an employee of an organization of auto parts and he uses own google advertisement page for the purpose of strategies to make perfect he owns advertisement campaigns for the google search. He values the scores of the optimization because Steve applies charge over the different layers of his ads strategies.

4 0
2 years ago
Write a method printShampooInstructions(), with int parameter numCycles, and void return type. If numCycles is less than 1, prin
iogann1982 [59]

Answer:

import java.util.Scanner;

public class nu3 {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       System.out.println("Enter number of cycles");

       int numCycles = in.nextInt();

       //Call the method

       printShampooInstructions(numCycles);

   }

   public static void printShampooInstructions(int numCycles){

                if (numCycles<1){

              System.out.println("Too few");

          }

          if (numCycles>4){

              System.out.println("Too Many");

          }

          else {

              for (int i = 1;i <= numCycles; i++) {

                  System.out.println( numCycles+ ": Lather and rinse");

                  numCycles--;

              }

              System.out.println("     Done");

          }

   }

}

Explanation:

This is solved using Java programming language

The method printShampooInstructions() is in bold in the answer section

I have also provided a complete program that request user to enter value for number of cycles, calls the method and passes that value to it

The logic here is using if .... else statements to handle the different possible values of Number of cycles.

In the Else Section a loop is used to decrementally print the number of cycles

4 0
2 years ago
Compare the encryption algorithms found in s-tools: idea, mdc, des, and 3des.
grin007 [14]
Are their answer chocies 

3 0
2 years ago
(1) Prompt the user to enter two words and a number, storing each into separate variables. Then, output those three values on a
denpristay [2]

Answer:Prompt the user to enter two words and a number, storing each into separate variables. Then, output those three values on a single line separated by a space. (Submit for 1 point) Ex: If the input is: yellow Daisy 6 the output after the prompts is: You entered: yellow Daisy 6 Note: User input is not part of the program output. (2) Output two passwords using a combination of the user input. Format the passwords as shown below. (Submit for 2 points, so 3 points total). Ex: If the input is: yellow Daisy 6 the output after the prompts is: You entered: yellow Daisy 6 First password: yellow_Daisy Second password: 6yellow6 (3) Output the length of each password (the number of characters in the strings). (Submit for 2 points, so 5 points total). Ex: If the input is: yellow Daisy 6 the output after the prompts is: You entered: yellow Daisy 6 First password: yellow_Daisy Second password: 6yellow6 Number of characters in yellow_Daisy: 12 Number of characters in 6yellow6: 8

I have tried several different ways of doing this, but I keep getting an error on line 6

Explanation:

7 0
1 year ago
Describe a strategy for avoiding nested conditionals. Give your own example of a nested conditional that can be modified to beco
Alex787 [66]

Answer:

One of the strategies to avoid nested conditional is to use logical expressions such as the use of AND & operator.

One strategy is to use an  interface class with a method. That method can be created to be used for a common functionality or purpose. This is also called strategy design pattern. You can move the chunk of conditional statement to that method. Then each class can implement that interface class and use that shared method according to their own required task by creating objects of sub classes and call that common method for any such object. This is called polymorphism.

Explanation:

Nested conditionals refers to the use of if or else if statement inside another if or else if statement or you can simply say a condition inside another condition. For example:

if( condition1) {  

//executes when condition1 evaluates to true

  if(condition2) {

//executes when condition1  and condition2 evaluate to true

  }  else if(condition3) {

 //when condition1 is true and condition3 is true

} else {

 //condition1  is true but neither condition2 nor conditions3 are true

}  }

The deeply nested conditionals make the program difficult to understand or read if the nested conditionals are not indented properly. Also the debugging gets difficult when the program has a lot of nested conditionals.

So in order to avoid nested conditionals some strategies are used such as using a switch statement.

Here i will give an example of the strategies i have mentioned in the answer.

Using Logical Expressions:

A strategy to avoid nested conditionals is to use logical expressions with logical operators such as AND operator. The above described example of nested conditionals can be written as:

if(condition1 && condition2){  //this executes only when both condition1 and condition2 are true

} else if(condition1 && condition3) {

this executes only when both condition1 and condition3 are true

} else if(condition1 ){

//condition1  is true but neither condtion2 nor condtion3 are true  }

This can further be modified to one conditional as:

if(!condition3){

// when  condition1 and condition2 are true

}

else

// condition3 is true

Now lets take a simple example of deciding to go to school or not based on some conditions.

if (temperature< 40)

{

   if (busArrived=="yes")

   {

       if (!sick)

       {

           if (homework=="done")

           {

               printf("Go to school.");

           }

       }                    

   }

}

This uses nested conditionals. This can be changed to a single conditional using AND logical operator.

if ((temperature <40) && (busArrived=="yes") &&

(!sick) && (homework=="done"))

{    cout<<"Eligible for promotion."; }

The second strategy is to use an interface. For example you can

abstract class Shape{

//declare a method common to all sub classes

  abstract public int area();

// same method that varies by formula of area for different shapes

}

class Triangle extends Shape{

  public int area() {

     // version of area code for Triangle

return (width * height / 2);

  }

}

class Rectangle extends Shape{

  public int area() {

     // version of area code for Rectangle

    return (width * height)

  }

}

// Now simply create Rectangle or Triangle objects and call area() for any such object and the relevant version will be executed.

4 0
2 years ago
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