Answer:
The number of once is 9.1
The number of hundreds is 8.9
Step-by-step explanation:
Given as :
The total of digits having ones and hundreds = 900
The sum of digits = 18
Let The number of ones digit = O
And The number of hundreds digit = H
So, According to question
H + O = 18 .........1
100 × H + 1 × O = 900 ........2
Solving the equation
( 100 × H - H ) + ( O - O ) = 900 - 18
Or, 99 H + 0 = 882
Or , 99 H = 882
∴ H = 
I.e H = 8.9
Put the value of H in eq 1
So, O = 18 - H
I.e O = 18 - 8.9
∴ O = 9.1
So, number of once = 9.1
number of hundreds = 8.9
Hence The number of once is 9.1 and The number of hundreds is 8.9
Answer
Answer:
Here, BRX and NJY are two triangles in which,
BR = 30 cm, RX = 40 cm, BX = 60 cm, NJ = 15 cm, JY = 20 cm and NY = 30 cm,
Also, m∠B = m∠N, m∠R = m∠J and m∠X = m∠Y,
By the property of congruence,
, 
and 
Thus, By AAA similarity postulate,
Hence, proved.
Answer:
F
Step-by-step explanation:
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Answer:
25
Step-by-step explanation:
had it on khan
Answer:
592,000
Step-by-step explanation:
The new dimensions are 500, 280, and 200. Multiply 2(500*280 + 500*200 + 280*200) to get the answer
