Answer:
120 of design B
Step-by-step explanation:
The profit per dollar cost for design A is (2500/1750 -1) ≈ 0.43. For design B, it is (2100/1200 -1) ≈ 0.75. Design B is more profitable and less expensive to make, so its production should be maximized.
For maximum profit, 120 jogging pants of design B should be made each week.
_____
The budget of 150,000 would allow 150,000/1,200 = 125 pants of design B to be made. The production limit of 120 pants does not use the entire budget.
Answer: OPTION A
Step-by-step explanation:
It is important to remember the "Angle Addition Postulate" in order to solve this exercise.
You have this larger angle:
According to the "Angle Addition Postulate", if the point "C" is in the interior of , then the measure of this angle can be obtained by adding the angle
and the angle
.
You can observe in the figure that:
Then you get that:
Therefore, the correct answer is Option A.
Answer:
Step-by-step explanation:
Answer:
The degrees of freedom are
And the p value is given by:
Since the p value for this cae is lower than the significance level of 0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true means for this case are significantly different
Step-by-step explanation:
When we have two independent samples from two normal distributions with equal variances we are assuming that
And the statistic is given by this formula:
Where t follows a t distribution with degrees of freedom and the pooled variance
is given by this formula:
The system of hypothesis on this case are:
Null hypothesis:
Alternative hypothesis:
We have the following data given:
represent the sample size for group 1
represent the sample size for group 2
represent the sample mean for the group 1
represent the sample mean for the group 2
represent the sample standard deviation for group 1
represent the sample standard deviation for group 2
First we can begin finding the pooled variance:
And the deviation would be just the square root of the variance:
The statistic is givne by:
The degrees of freedom are
And the p value is given by:
Since the p value for this cae is lower than the significance level of 0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true means for this case are significantly different