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wlad13 [49]
2 years ago
15

A RSS Clothing manufacturer makes two types of jogging pants, design A and design B. The design A jogging pants sells to the ret

ail stores for 2,500each and the design B jogging pants for 2,100. The cost for manufacturing each design A is 1,750 and the cost of each design B is 1,200. If the manufacturer makes no more than 120 jogging a week and budget no more than 150,000 per week, how many of each type should be made to maximize profit?

Mathematics
1 answer:
nikdorinn [45]2 years ago
8 0

Answer:

  120 of design B

Step-by-step explanation:

The profit per dollar cost for design A is (2500/1750 -1) ≈ 0.43. For design B, it is (2100/1200 -1) ≈ 0.75. Design B is more profitable and less expensive to make, so its production should be maximized.

For maximum profit, 120 jogging pants of design B should be made each week.

_____

The budget of 150,000 would allow 150,000/1,200 = 125 pants of design B to be made. The production limit of 120 pants does not use the entire budget.

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Here is a scenario that came up in the nationally syndicated column called "Ask Marilyn" in Parade Magazine. Suppose a certain d
goldenfox [79]

Answer:

                           Drug User   Not a drug user    Totals

Test positive       475                     475                  950

Test negative      25                      9025               9050

Totals                   500                   9500               10,000

Step-by-step explanation:

                           Drug User   Not a drug user    Totals

Test positive       475                     475                  950

Test negative      25                      9025               9050

Totals                   500                   9500               10,000

As we know that 5% of all people are drug users

Total drug users=5% of 10,000=0.05(10,000)=500

Total non drug users= Total people - drug users= 10,000-500=9500

or total non drug users=95% of 10,000=0.95(10,000)=9500

Test is correct for 95% of times means that 95% times drug users test results is positive and non drug users test results is negative.

Test positive for drug user= 95% of 500=0.95(500)=475

Test negative for non drug user= 95% of 500 = 0.95(9500)=9025

Test is correct for 95% of times and it means that 5% of times test is not correct. It means that 5% of times drug users test results is negative and non drug users test results is positive.

Test negative for drug user= 5% of 500=0.05(500)=25

Test positive for non drug user= 5% of 9500 = 0.05(9500)=475

4 0
1 year ago
Find the first, fourth, and eighth terms of the sequence. A(n) = –3 • 2^n–1
Sphinxa [80]
A(n) = –3 • 2⁽ⁿ⁻¹⁾

for n = 1 ,  A₁ = -3.(2)⁰ = -3
for n = 2 ,  A₂ = -3.(2)¹ = -6
for n = 3 ,  A₃ = -3.(2)² = -12
for n = 4 ,  A₄ = -3.(2)³ = -24
...........................................
for n = 8 ,  A₈ = -3.(2)⁷ = -384


4 0
1 year ago
James is the manager at an entertainment arena that draws an average 7,000 patrons per event. Each ticket taker can process 350
Elina [12.6K]

Answer:

No. James didn't have enough ticket takers to process the average number of patrons hat usually attend the events.

He need to hire 2 more ticket taker (i.e 20 ticket takers) in order to process the average number of patrons hat usually attend the events.

Step-by-step explanation:

Given:

Average amount of patron per event= 7000

Each ticket taker can process = 350

Number of ticket takers hired = 18

We need to find the whether he hire enough to process the average number of patrons that usually attend the events.

Solution:

We will find the Average amount of patron ticket takers can process.

Now we can say that

Average amount of patron ticket takers can process is equal to Each ticket taker can process multiplied by Number of ticket takers hired.

framing in equation form we get;

Average amount of patron ticket takers can process = 350 \times 18 = 6300\ patrons

Hence With the required hires James cannot fully process the patrons usually attending the event.

To find how many ticket takers required we will divide average number of patrons with  Each ticket taker can process.

framing in equation form we get;

ticket takers required = \frac{7000}{350}=20

hence In order t process the the average number of patrons that usually attend the events James will require 20 ticket takers.

6 0
1 year ago
For the diagram below figure b is a reflection of y=2x of the line y =x
Scilla [17]
The equation of the line would be y = (1/2)x.

To find the equation of a line that is reflected through the line y = x, we just switch the x and y. Then, solve for y.

y = 2x
x = 2y
0.5x = y


5 0
1 year ago
Evaluate the triple integral ∭ExydV where E is the solid tetrahedon with vertices (0,0,0),(5,0,0),(0,9,0),(0,0,4).
Elan Coil [88]

Answer: \int\limits^a_E {\int\limits^a_E {\int\limits^a_E {xy} } \, dV = 1087.5

Step-by-step explanation: To evaluate the triple integral, first an equation of a plane is needed, since the tetrahedon is a geometric form that occupies a 3 dimensional plane. The region of the integral is in the attachment.

An equation of a plane is found with a point and a normal vector. <u>Normal</u> <u>vector</u> is a perpendicular vector on the plane.

Given the points, determine the vectors:

P = (5,0,0); Q = (0,9,0); R = (0,0,4)

vector PQ = (5,0,0) - (0,9,0) = (5,-9,0)

vector QR = (0,9,0) - (0,0,4) = (0,9,-4)

Knowing that cross product of two vectors will be perpendicular to these vectors, you can use the cross product as normal vector:

n = PQ × QR = \left[\begin{array}{ccc}i&j&k\\5&-9&0\\0&9&-4\end{array}\right]\left[\begin{array}{ccc}i&j\\5&-9\\0&9\end{array}\right]

n = 36i + 0j + 45k - (0k + 0i - 20j)

n = 36i + 20j + 45k

Equation of a plane is generally given by:

a(x-x_{0}) + b(y-y_{0}) + c(z-z_{0}) = 0

Then, replacing with point P and normal vector n:

36(x-5) + 20(y-0) + 45(z-0) = 0

The equation is: 36x + 20y + 45z - 180 = 0

Second, in evaluating the triple integral, set limits:

In terms of z:

z = \frac{180-36x-20y}{45}

When z = 0:

y = 9 + \frac{-9x}{5}

When z=0 and y=0:

x = 5

Then, triple integral is:

\int\limits^5_0 {\int\limits {\int\ {xy} \, dz } \, dy } \, dx

Calculating:

\int\limits^5_0 {\int\limits {\int\ {xyz}  \, dy } \, dx

\int\limits^5_0 {\int\limits {\int\ {xy(\frac{180-36x-20y}{45} - 0 )}  \, dy } \, dx

\frac{1}{45} \int\limits^5_0 {\int\ {180xy-36x^{2}y-20xy^{2}}  \, dy } \, dx

\frac{1}{45} \int\limits^5_0  {90xy^{2}-18x^{2}y^{2}-\frac{20}{3} xy^{3} } \, dx

\frac{1}{45} \int\limits^5_0  {2430x-1458x^{2}+\frac{94770}{125} x^{3}-\frac{23490}{375}x^{4}  } \, dx

\frac{1}{45} [30375-60750+118462.5-39150]

\int\limits^5_0 {\int\limits {\int\ {xyz}  \, dy } \, dx = 1087.5

<u>The volume of the tetrahedon is 1087.5 cubic units.</u>

3 0
1 year ago
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