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taurus [48]
2 years ago
4

Calculate the contact angle (in deg) for the smaller of two pulleys with diameters of 500mm and 200mm. The tension ratio is 3:1

and distance between parallel shafts is 700mm

Engineering
1 answer:
GrogVix [38]2 years ago
4 0

Answer:

\theta _A=155.25^{\circ}

Explanation:

Given that

D_B=500 mm,D_A=200 mm

Distance between pulleys= 700 mm

We have to find contact angle

In general application pulleys are connects in open configuration,So the contact angle given as follows

For small pulley

\theta _A=\pi +2sin^{-1}\dfrac{R_A-R_B}{C}

\theta _A=\pi +2sin^{-1}\dfrac{100-250}{700}

\theta _A=155.25^{\circ}

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A deep drawing operation is performed in which the inside of the cylindrical cup has a diameter of 4.25 in and a height = 2.65 i
Softa [21]

Answer:

drawing ratio = 1.81176

reduction = 0.4480 = 44.80 %

drawing force is = 162724.682 lb

blank holder force = 95481.10 lb

Explanation:

given data

cylindrical cup diameter = 4.25 in

cup height = 2.65 in

stock thickness = 3/16 in

blank diameter = 7.7 in

Punch and die radii = 5/32 in

so Punch diameter will be = 2 ×  5/32 in = 0.3125 in

tensile strength = 65,000 lb/in²

yield strength = 32,000 lb/in²

shear strength of 40,000 lb/in²

to find out

(a) drawing ratio, (b) reduction, (c) drawing force, and (d) blankholder force

solution

first we get drawing ratio hat is express as

drawing ratio = \frac{blank\ diameter}{cup\ diameter}     ..................1

put here value

drawing ratio = \frac{7.7}{4.25}

drawing ratio = 1.81176

and

reduction will be here

reduction = \frac{blank\ diameter - cup\ diameter}{blank\ diameter}  .................2

reduction = \frac{7.7 - 4.25}{7.7}

reduction = 0.4480 = 44.80 %

and

drawing force will be

drawing force is = k× π× cup diameter ×  stock thickness × tensile strength   ........................3

here k = 1

so put here value

drawing force is = 1 × π× 4.25 × \frac{3}{16} × 65000

drawing force is = 162724.682 lb

and

blank holder force will be here as

blank holder force = maximum punch load × \frac{1}{3}     ........................4

so here maximum punch load will be

maximum punch load = π × punch diameter × stock thickness × tensile strength × ( \frac{blank\ diameter}{punch\ diameter} - 0.7 )     .......................5

here 0.7 is correction factor

maximum punch load = π × 0.3125 × \frac{3}{16}  × 65000 × ( \frac{7.7}{0.3125} - 0.7 )

maximum punch load  = 286443.30 lb

so

blank holder force =  286443.30 × \frac{1}{3}

blank holder force = 95481.10 lb

4 0
2 years ago
A signalized intersection approach has three lanes with no exclusive left or right turning lanes. The approach has a 40-second g
ipn [44]

Answer:

786.01

Explanation:

Calculate the saturation flow rate by using the following equation

S = 3600/h, where h is the saturation headway

S = 3600/2.48 = 1452 veh/hg

<u>Calculate the effective green time</u>

G(i) = G(i) + Y(i) – t(Li), where G(i) is the actual green time for movement, Y(i) is the sum of yellow and all red intervals for movement, and t(Li), is the total lost time for movement

G(i) = 40, Y(i) = 4, t(Li) = 2.3 + 1.1 = 3.4

G(i) = 40 + 4 – 3.4 = 40.6

<u>Calculate the capacity of an intersection approach by using the following equation</u>

C(i) = s(i) [g(i)/C], where s(i) the saturation flow rate, g(i) is the effective green time, and C is the cycle length

s(i) = 1452, g(i) = 40.6, C = 75

C(i) = 1452 x (40.6/75) = 786.01 veh/h/ln

The capacity of intersection approach is 786.01

6 0
2 years ago
The gas stream from a sulfur burner is composed of 15-mol% SO2, 20-mol% O2, and 65-mol% N2. This gas stream at 1 bar and 480?C e
galben [10]

Answer: the equilibrium conversion is 0.15 or 15mole %

K=1.33

Explanation:

Given the mole percent of the gases to be as follows

SO2(g) =15% = 0.15mol

O2(g) =20% = 0.20mol

N2(g) = 65% = 0.65mol

The equilibrium conversion reaction is given by

2SO2(g) + O2(g) <------> 2SO3(g)

2 1. 2

According to the reaction 2 moles of SO2 is converted to get 2 mole of SO3

Therefore 0.15 mole will produce 0.15 mole of SO3

So at equilibrium:

2SO2(g) + O2(g) ------> 2SO3(g)

0.15. 0.075. 0.15

Now the equilibrium constant K is given by:

K = [SO3]²/[SO2]²[O2]

Since the container is constant for all the reactants we can neglect the container capacity and use the mole as percent concentration.

K = [0.15]²/[0.15]²[0.075]

K = 1/0.075

K= 1.33

6 0
2 years ago
A steady, incompressible, two-dimensional velocity field is given by the following components in the x-y plane: u=1.85+2.05x+0.6
AnnZ [28]

Answer:

\frac{du}{dt} = 1.515

\frac{dv}{dt} = 5.511

Explanation:

The acceleration field is obtained by deriving the components in function of the time. That is to say:

\frac{du}{dt}=2.05\cdot \frac{dx}{dt}+0.656\cdot \frac{dy}{dt}\\\frac{dv}{dt} = -2.18\cdot \frac{dx}{dt} -2.05\cdot \frac{dy}{dt}

Where \frac{dx}{dt} = u and \frac{dy}{dt} = v.

The velocity components at given point are, respectively:

u = 2.424

v=-5.266

Lastly, the acceleration components are found:

\frac{du}{dt} = 1.515

\frac{dv}{dt} = 5.511

7 0
2 years ago
The atomic radii of a divalent cation and a monovalent anion are 0.77 nm and 0.136 nm, respectively.1- Calculate the force of at
MrMuchimi

Answer:

A) attractive force between ions = 5.09x10^-19 N of attractive force

B) there will be no repulsion since both ions have opposite charges.

Explanation:

Detailed explanation and calculation is shown in the image below.

5 0
2 years ago
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