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2 years ago

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Jillian’s school is selling tickets for a play. The tickets cost $10.50 for adults and $3.75 for students. The ticket sales for

opening night totaled $2071.50. The equation 10.50 a plus 3.75 b equals 2071.50, where a is the number of adult tickets sold and b is the number of student tickets sold, can be used to find the number of adult and student tickets. If 82 students attended, how may adult tickets were sold?

2 answers:

gizmo_the_mogwai [7]2 years ago

8 0

Answer:

The number of the adult tickets is 168

Step-by-step explanation:

* Lets explain how to solve the problem

- The adults ticket costs $10.50

- The students ticket costs $3.75

- The total money of the opening night is $2071.50

- The equation of the total money earned in the opening night is:

10.50 a + 3.75 b = 2071.50, where a is the number of the adult ticket

and b is the number of the student ticket

- There were 82 students attended

* Lets solve the problem

∵ 10.50 a + 3.75 b = 2071.50

∵ The number of the students attended is 82

∵ b is the number of the students

∴ b = 82

- Substitute the value of b in the equation

∴ 10.50 a + 3.75(82) = 2071.50

∴ 10.50 a + 307.5 = 2071.50

- Subtract 307.5 from both sides

∴ 10.50 a = 1764

- Divide both sides by 10.50

∴ a = 168

∵ a is the number of the adult tickets

∴ The number of the adult tickets is 168

rjkz [21]2 years ago

8 0

Answer:

168

Step-by-step explanation:

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