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3241004551 [841]
2 years ago
6

Zoe has 5 pounds of potatos she has multiple recipes that require 3/4 pound of potatoes how many recipes will she be able to mak

e
Mathematics
2 answers:
Natali [406]2 years ago
5 0
Amount of potatoes that Zoe has = 5 pounds
Quantity of potatoes that Zoe need for each recipe = 5/(3/4) 
                                                                                 = 5 * (4/3) 
                                                                                 = 20/3 
                                                                                 = 6 2/3 
From the above deduction, we can conclude that only 6 recipes can be made. The remaining amount of 2/3 will remain unused. I hope the procedure is clear enough for you to understand.
Amanda [17]2 years ago
4 0
<h2>Answer:</h2>

The number of recipe she could make is:

                              6

<h2>Step-by-step explanation:</h2>

It is given that:

Zoe has 5 pounds of potatoes she has multiple recipes that require 3/4 pound of potatoes.

Hence, the total number of recipes she can make is:

Ratio of the total amount of potatoes she has to the number of pounds i.e. amount  of potatoes required for one recipe.

Hence, we have:

\text{Number of recipes}=\dfrac{5}{\dfrac{3}{4}}\\\\i.e.\\\\\text{Number of recipes}=\dfrac{5\times 4}{3}\\\\\text{Number of recipes}=\dfrac{20}{3}\\\\\text{Number of recipes}=6.333

which in whole number is:

\text{Number of recipes}=6

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Quadrilateral ABCD in the figure below represents a scaled-down model of a walkway around a historic site. Quadrilateral EFGH re
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Answer:

<em>165ft</em>

Step-by-step explanation:

Ratio of actual walkway and a model is :

60  ( Ft ) : 15 ( in)  or : 15 : 1

EF = 60 Ft,

FG = 30 Ft,

GH = 30 Ft,

HE = 45 Ft.

60 + 30 + 30 + 45 = 165 Ft



8 0
2 years ago
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An automated egg carton loader has a 1% probability of cracking an egg, and a customer will complain if more than one egg per do
vaieri [72.5K]

Answer:

a) Binomial distribution B(n=12,p=0.01)

b) P=0.007

c) P=0.999924

d) P=0.366

Step-by-step explanation:

a) The distribution of cracked eggs per dozen should be a binomial distribution B(12,0.01), as it can model 12 independent events.

b) To calculate the probability of having a carton of dozen eggs with more than one cracked egg, we will first calculate the probabilities of having zero or one cracked egg.

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P(k=0)=\binom{100}{0}p^0(1-p)^{100}=0.99^{100}=0.366

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Alan says that two lines in the coordinate plane are perpendicular if and only if the slopes of the lines are m and 1m. Identify
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But we can not really divide by zero, so we should state that:

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Total= 2.95(x)+39.95(12)

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