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Tema [17]
2 years ago
5

A random sample of house sizes in major city has a sample mean of x¯=1204.9 sq ft and sample standard deviation of s=124.6 sq ft

. Use the Empirical Rule to determine the approximate percentage of house sizes that lie between 955.7 and 1454.1 sq ft
Mathematics
1 answer:
Svet_ta [14]2 years ago
6 0

Answer: 95%

Step-by-step explanation:

The Empirical rule says that about 68% of the data is within one standard deviation of the mean; about 95% of the data is within two standard deviations of the mean ; about 99.7% of the data is within three standard deviations of the mean.

Given : Sample mean : \overline{x}=1204.9\text{ sq.ft.}

Standard deviation: s=124.6\text{ sq. ft.}

To find the percentage of house sizes that lie between 955.7 and 1454.1 sq ft.

We can write it as 955.7=1204.9-249.2=1204.9-2(124.6)

and 1454.1=1204.9+249.2=1204.9+2(124.6)

Thus, 955.7 is 2 standard deviations left from the means and 1454.1 is 2 deviations right from the mean.

Then by empirical rule , about 95% of house sizes that lie between 955.7 and 1454.1 sq ft .

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Wewaii [24]

Answer:

132 m².

Step-by-step explanation:

What's the surface area of each lateral face of this pyramid?

Each lateral face of this pyramid is a triangle, with

  • a height of 8 meters
  • on a base 6 meters.

The base of this pyramid is a square. As a result, all four lateral sides are congruent. The area of each of these triangle is thus

\displaystyle \frac{1}{2}\times \text{Base}\times \text{Height} = \rm \frac{1}{2} \times 6 \times 8 = 24\; m^{2}.

The base of this pyramid is a square. The length of a side of this square is 6 meters. The area of the base will be

\text{Side}^{2} = \rm 6^{2} = 36\; m^{2}.

Put the five faces together to get the total surface area of this square pyramid:

\rm 4\times 24 + 36 = 132\; m^{2}.

8 0
2 years ago
A village was founded four hundred years ago by a group of 20 people. In this village, the population triples every one hundred
Paha777 [63]

Answer:

Step-by-step explanation:

Treat this like compound interest:  Use A = P(1 + r)^t.

Here, P is the initial population and A is 3 times that, or 3P.  Since P = 20 people, 3P = 60 people,

and this population is reached after 100 years.

We need to determine r, substitute its value into the formula A = P(1 + r)^t, and then determine the population of the village after 400 years.

60 = 20(1 + r)^100

Simplifying, 3 = (1 + r)^100.

Taking the natural log of both sides,

ln 3 = 100 ln (1 + r), or

                   ln 3

ln (1 + r) = ---------------

                    100

              = 1.0986 / 100 = 0.01986

We must solve this for r.  Raising e to the power ln (1 + r), on the left side of an equation, and raising e to the power 0. 01986 on the right side, we get:

1 + r = 3, so r must = 2.

Now find the pop of the village today.  Use the same equation:  A = P (1+r)^t.

A = 20(1 +2)^4 (hundreds),

or

A = 20(3)^4, or

A = 81

The population after 400 years is 81.

8 0
2 years ago
For all real numbers a and b, 2a • b = a2 + b2 Is this true or false? Explain why it false or true.
Andru [333]

Answer:

It's false.... correct is a2+2ab+b2

Step-by-step explanation:

This cannot be factored anymore although. when we try to substitute a with 5 and b with 2, the answer in the right hand side of the equation is -9.

That's why it's false.

3 0
2 years ago
Simplify the function f (x) = one-third (81) Superscript StartFraction 3 x Over 4 EndFraction. Then determine the key aspects of
Nikitich [7]

Answer:

The answer is given below

Step-by-step explanation:

Given that:

f(x)=\frac{1}{3}(81)^ \frac{3x}{4} \\Using\ exponent\ rule:a^{xy}=a^xa^y\\f(x)=\frac{1}{3}(81^{1/4})^ {3x}\\f(x)=\frac{1}{3}(3})^ {3x}\\f(x)=\frac{(3)^ {3x}}{3^1} \\Using\ exponent\ rule:a^x/a^y=a^{x-y}\\f(x)=3^ {3x-1}

The function is an exponential function.

The domain is the set of all independent variables i.e the input values (x values). For an exponential function, the domain is the set of all real numbers. That is:

Domain: x = (-∞, ∞)

The range is the set of all dependent variables i.e the values of y. For an exponential function, the range is the set of all real numbers greater than zero. That is:

Range: y = (0, ∞)

8 0
2 years ago
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erastova [34]
I would say the answer is A.
4 0
2 years ago
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