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kati45 [8]
2 years ago
4

Monty borrowed $10,500 and promises to make three equal payments, one in 6 months, one in 12 months, and one in 18 months. If mo

ney is worth 10% compounded quarterly, what is the size of the equal payments? Use 18 months as the focal date.
Mathematics
1 answer:
Stella [2.4K]2 years ago
4 0

Answer:

The money will be paid in three equal shares of $4056.48.

Step-by-step explanation:

This is a compound interest problem

Compound interest formula:

The compound interest formula is given by:

A = P(1 + \frac{r}{n})^{nt}

A: Amount of money(Balance)

P: Principal(Initial deposit)

r: interest rate(as a decimal value)

n: number of times that interest is compounded per unit t

t: time the money is invested or borrowed for

In our problem, we have

A: The amount of money that will have to be paid

P = $10,500(The initial money)

r = 0.1

n = 3(the money is compounded each 4 months, and there 12 months a year, so the money is compounded 3 times a year).

t = 1.5(18 months is a year and half)a year.

So:

A = 10,500(1 + \frac{0.1}{3})^{3*1.5}

A = $12,169.46

$12,169.46 is the amount of money that Monty will have to pay. It will be paid in 3 equal shares of 12,169.46/3 = $4056.48.

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Answer:

Step-by-step explanation:

The origin (x,y) is (0,0)

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2 years ago
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OK, so this is assuming we are considering that the first three kids to solve ARE NOT in the first day.


So we have 3 kids and it doubles

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Day 2 : 12

Day 3 : 24

Day 4 : 48

Day 5 : 96

Day 6 : 192

Day 7: 384


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The equation:

(3 * 2)^x = 384


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In expanded notation, the hexadecimal 74AF16 is (7*4096) + (4*256) + (A*16) + (F*1). When converting from hexadecimal to decimal
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Answer:

F is assigned the value of 15

74AF_{16} = 29871_{10}

Step-by-step explanation:

Hexadecimal number system is base 16 and it contain the following numbers:

0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F

A has a value of 10

B has a value of 11

C has a value of 12

D has a value of 13

E has a value of 14

F has a value of 15

By completing the expanded notation:

(7*4096) + (4*256) + (A * 16) + (F *1)\\= (7*4096) + (4*256) + (10 * 16) + (15 *1)\\= 28672 + 1024 + 160 + 15\\= 29871

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2 years ago
Fez rolls 2 fair dice and adds the results from each. Work out the probability of getting a total less than 6.
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Answer:

The probability of getting  sum of two dice is less than six

P(E) =0.25

Step-by-step explanation:

<u><em>Step(i):-</em></u>

The total number of cases n(S) = 6² = 36

Let 'E' be the event of getting  sum of two dice is less than six

{(1,2) , (1,3),(1,4),(2,1),(2,2),(2,3),(3,1),(3,2),(4,1)}

n(E) =9

<u><em>Step(ii):-</em></u>

The probability of getting  sum of two dice is less than six

P(E) = \frac{n(E)}{n(S)}

P(E) = \frac{9}{36} = \frac{1}{4}

P(E) = 0.25

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