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Ludmilka [50]
2 years ago
12

702 001 in expanded form

Mathematics
2 answers:
hodyreva [135]2 years ago
8 0

Answer:

700000+ 0+2000+0+0+1  

Step-by-step explanation:

Given : Number 702001

To write : In expanded form

Solution :

Expanded form - When we expand a number to show the value of each digit, is that number in expanded form.

The place value were defined as

Hundred.Th     Ten.Th     Thousands   Hundreds  Tens   ones

    7                       0                2                    0              0         1

Expanded notation =  7\times 10^5+ 0\times10^4+2\times 10^3+0\times10^2+0\times10^1+1\times10^0      

=700000+ 0+2000+0+0+1                      

Required expanded form.                                                                                          

OLga [1]2 years ago
3 0
700,000+2,000+1, should be your answer.
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a teacher needs 70 lengths of string cut to 40 cm each. If balls of string are 10 m long how many balls will be needed
LenKa [72]
A meter is 100 cm. A ball of string has 10m of string, and you multiply 10m by 100cm, you get 1,000cm. Then you multiply 40cm by 2, and you get 80cm, or two lengths of string. Then you multiply 35, which is half of 70, by 80, and that is 2,800 cm.
2,800
÷40cm=70
And 100cm=1m.
The teacher will therefore need 28 balls of string.
7 0
2 years ago
A cell tower is located 3 miles east and 4 miles north of the center of a small town. The cell tower has a coverage radius of 3
butalik [34]

Answer:

The answer is below

Step-by-step explanation:

A cell tower is located 3 miles east and 4 miles north of the center of a small town. The cell tower has a coverage radius of 3 miles.

a) Start by drawing a diagram of this situation. Your diagram might include a coordinate plane, the cell tower, and a circle representing the cell tower's coverage boundary.

a) A house is located 5 miles north of the center of the town and is to the east of the cell tower. If the house lies on the boundary of the cell tower's coverage, how far east of the center of the town is the house?

Answer:

Let the center of the town represent the origin (0,0). Also 1 unit = 1 mile. Since the cell tower is located 3 miles east and 4 miles north of the center of a small town, it is represented by A(3, 4)

The cell tower has a coverage of radius 3 miles. This can be represented by a circle with equation:

(x - a)² + (y - b)² = r². where (a,b) is the center of the circle and r is the radius. Hence:

(x - 3)² + (y - 4)² = 3²

(x - 3)² + (y - 4)² = 9

The diagram is drawn using geogebra.

b) The house is 5 miles north. It can be represented by y = 5 line.

To find the distance east of the house we have to substitute y = 5 and solve for x, hence:

(x - 3)² + (y - 4)² = 9

(x - 3)² + (5 - 4)² = 9

(x - 3)² + 1 = 9

(x - 3)² = 8

(x - 3) = √8

x - 3 = ±2.83

x = 3 ± 2.83

x = 5.83 or 1.83

Since it is to the east to the cell tower, hence x = 5.83.

Therefore the house is located 5.83 miles to the east of the cell tower

8 0
2 years ago
Line segment JL is an altitude in triangle JKM. Which statement explains whether JKM is a right triangle? Round measures to the
natulia [17]

Answer:

C. JKM is not a right triangle because KM ≠ 15.3.

Step-by-step explanation:

We can see from our diagram that triangle JKM is divided into right triangles JLM and JLK.  

In order to triangle JKM be a right triangle KM^{2}=JK^{2}+JM^{2}.

We will find length of side KM using our right triangles JLM and JLK as KM=KL+LM.  

Using Pythagorean theorem in triangle JLM we will get,

LM=\sqrt{JM^{2}-JL^{2}}

LM=\sqrt{8^{2}-5^{2}}

LM=\sqrt{64-25}

LM=\sqrt{39}=6.244997998\approx 6.24

Now let us find length of side KL.

KL=\sqrt{JK^{2}-JL^{2}}  

KL=\sqrt{13^{2}-5^{2}}

KL=\sqrt{169-25}

KL=\sqrt{144}=12

Now let us find length of KM by adding lengths of KL and LM.

KM=12+6.24=18.24

Now let us find whether JKM is right triangle or not using Pythagorean theorem.

KM^{2}=JK^{2}+JM^{2}  

18.24^{2}=13^{2}+8^{2}

18.24^{2}=169+64

18.24^{2}=233

Upon taking square root of both sides of equation we will get,

18.24\neq 15.264337522473748

18.2\neq 15.3  

We have seen that KM equals 18.2 and in order to JKM be a right triangle KM must be equal to 15.3, therefore, JKM is not a right triangle and option C is the correct choice.    

6 0
2 years ago
Read 2 more answers
The goals against average (A) for a professional hockey goalie is determined using the formula A=60(g/2). In the formula, g repr
maks197457 [2]

Answer:

g = At/60

Step-by-step explanation:

Given:

A = 60(g/t)  

60(g/2) is a mistake in the question which the question                                        has corrected in the comments)

A is the average for a professional hockey goalie.

g is the number of goals scored against the goalie.

t represents the time played in minutes.

Finding 'g':

A = 60(g/t)

can be written as A = (60*g)/t

Multiplying by 't' on both sides:

At = (60*g)*t/t

At = 60*g

Dividing by '60' on both sides:

At/60 = 60*g/60

At/60 = g

⇒ g = At/60

3 0
2 years ago
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A softball pitcher throws a softball to a catcher behind home plate. The softball is 3 feet above the ground when it leaves the
Xelga [282]

The <em><u>correct answer</u></em> is:

h(t) = –16t² + 50t + 3

Explanation:

The general form of an equation such as this is h(t) = at² + v₀t + h₀, where a is the constant due to gravity, v₀ is the initial velocity and h₀ is the initial height.

We are given that the constant due to gravity is -16.

The initial velocity is 50, and the initial height is 3; this gives us the equation

h(t) = -16t² + 50t + 3

5 0
2 years ago
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