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Aneli [31]
2 years ago
5

A spyware is trying to break into a system by guessing its password. It does not give up until it tries 1 million different pass

words. What is the probability that it will guess the password and break in if by rules, the password must consist of
(a) 6 different lower-case letters
(b) 6 different letters, some may be upper-case, and it is case-sensitive
(c) any 6 letters, upper- or lower-case, and it is case-sensitive
(d) any 6 characters including letters and digits
Mathematics
1 answer:
Juliette [100K]2 years ago
7 0

Answer: So our limit is 1 million attempts.

a) 6 lower case letters.

Think in 6 blank spaces where you can put one letter, so in each space you have 26 options, so the total of combinations is 26^{6} = 308915776.

so if you have 1 million attempts, then 1000000/308915776 = 0.00323

so you have 0.32% chances of breaking the code.

b) 6 different letters, some may be upper-case, and it is case-sensitive

Again 6 blank spaces, in the first you can put 26 letters,  and because its case sensitive, you have 52 options, in the second space, you will have 25 posible letters, and 50 options, and so on.

So the total combinations are 52*50*48*46*44*42 = 10608998400

and the probability of breaking it with 1 mill attempts is = 0.009%

(c) any 6 letters, upper- or lower-case, and it is case-sensitive

same as the first case, but here you have 26 lower case and 26 upper, so you have 52^{6} = 19770609664 combinations

and in 1 mill attempts the probability of breaking it is 0.0005%

(d) any 6 characters including letters and digits

Here you have 26 letters and 10 numbers, so the total combinations are :

36^{6} = 2176782336

and the probability of breaking it will be 0.004%

were in all cases you must think that each attempt made by the spyware is a different combination, so the one million tries are different combinations.

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Doris ran 2.5 kilometers, then sprinted 300 meters and finally walked 1 4 of the distance she sprinted. How many meters did she
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Answer:

She traveled a total of 2875 metres during practice.

Step-by-step explanation:

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To find the total distance that she traveled, we simply add the distance that she ran, sprinted and walked.

We will convert all distances to metres.

She ran 2.5 kilometres:

1 km = 1000 m

2.5 km = 2.5 * 1000 = 2500 m

So, she ran 2500 m.

She sprinted 300 m.

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1/4 * 300 = 75 m

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2500 + 300 + 75 = 2875 m

She traveled a total of 2875 metres during practice.

5 0
2 years ago
Expand (2x-3y)^4 using Pascal's Triangle. Show work
deff fn [24]
(2x+3y)⁴
1) let 2x = a   and 3y = b

(a+b)⁴ = a⁴ + a³b + a²b² + ab³ + b⁴
Now let's find the coefficient of each factor using Pascal Triangle
     
                     0     |               1
                     1     |            1    1
                     2     |          1   2   1
                     3     |         1  3   3   1
                     4     |       1  4   6    4  1

0,1,2,3,4,.. represent the exponents of binomials 
Since our binomial has a 4th exponents, the coefficients are respectively:

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Now replace a and b by their real values in (1):

2⁴x⁴ +(4)8x³(3y) + (6)(2²x²)(3²y²) + (4)(2x)(3³y³) + (1)(3⁴)(y⁴)

16x⁴ + 96x³y + 216x²y² + 216xy³ + 81y⁴
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2 years ago
Conscientiousness is a tendency to show self-discipline, act dutifully, and aim for achievement. The trait shows a preference fo
MAVERICK [17]

Answer:

a

The Null hypothesis represented as

     H_0: \mu_1 -  \mu_2  = 0

   

The Alternative hypothesis represented as

     H_a: \mu_1 -  \mu_2  <  0

b

p-value =  P(Z <  -3.37  )  = 0.000376

c

There is insufficient evidence to conclude that graduate students score higher, on average, on the HPI than undergraduate students

Step-by-step explanation:

From the question we are told that

   The population size is  n= 650

    The  sample size for graduates is  n_1 =  300

     The sample  mean for graduates is \= x _1 =  148

      The sample  standard deviation for graduates is \sigma_1  =  16

    The  sample size for under-graduates is n _2 = 350

         The sample  mean for under-graduates is \= x _2 =  153

         The sample  standard deviation for graduates is \sigma_2  =  21

The Null hypothesis represented as

     H_0: \mu_1 -  \mu_2  = 0

   

The Alternative hypothesis represented as

     H_a: \mu_1 -  \mu_2  <  0

Where \mu_1 \ and \  \mu_2 are the population mean

  Now the test statistic is mathematically represented as

          t =  \frac{(\= x_1 - \= x_2 ) }{ \sqrt{ \frac{ (n_1 - 1 )\sigma_1 ^2 + (n_2 - 1)\sigma_2^2}{n_1 +n_2 -2} }  * \sqrt{ \frac{1}{n_1}  + \frac{1}{n_2} } }

substituting values

       t =  \frac{(148 - 153 ) }{ \sqrt{ \frac{ (300- 1 )16 ^2 + (350 - 1) 21^2}{300 +350 -2} }  * \sqrt{ \frac{1}{300}  + \frac{1}{350} } }

      t = -3.37

The p-values is mathematically evaluated as

     p-value =  P(Z <  -3.37  )  = 0.000376

The above answer is gotten using a p-value calculator  at (0.05) level of significance

     Looking the p-value we see that it is less than the level of significance (0.05)  so Null hypothesis is rejected

Hence there is insufficient evidence to conclude that graduate students score higher, on average, on the HPI than undergraduate students

   

6 0
2 years ago
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Inessa05 [86]
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3            $16,621.20
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We need to get the increase of the net profit of the current year from the previous year.

Percentage increase = (Current year - Previous Year)/ Previous Year    * 100%

Year 2:  (15,390 - 14, 250) / 14,250   * 100% = 0.08 * 100% = 8%
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Every year the net income increases by 8%. So, the net income in Year 5 will be:

17,950.90 x 1.08 = 19,386.97  Choice D.

8 0
2 years ago
Read 2 more answers
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