For this case we have the following polynomial:
The first thing to do is to place the variables on the same side of the equation.
We have then:
We complete the square by adding the term (b / 2) ^ 2 on both sides of the equation.
We have then:
Rewriting we have:
Therefore, the solutions are:
Answer:
the solution set of the equation is:
This is an expression if she only gets pedicure
y = 35
If she wants to get massage, multiply the cost for a minute with the number of minutes.
Find cost per minute first
cost = 50/20
cost = 2.5
So the expression would be
y = 35 + 2.5x
y = 2.5x + 35
In a large population, 61% of the people are vaccinated, meaning there are 39% who are not. The problem asks for the probability that out of the 4 randomly selected people, at least one of them has been vaccinated. Therefore, we need to add all the possibilities that there could be one, two, three or four randomly selected persons who were vaccinated.
For only one person, we use P(1), same reasoning should hold for other subscripts.
P(1) = (61/100)(39/100)(39/100)(39/100) = 0.03618459
P(2) = (61/100)(61/100)(39/100)(39/100) = 0.05659641
P(3) = (61/100)(61/100)(61/100)(39/100) = 0.08852259
P(4) = (61/100)(61/100)(61/100)(61/100) = 0.13845841
Adding these probabilities, we have 0.319761. Therefore the probability of at least one person has been vaccinated out of 4 persons randomly selected is 0.32 or 32%, rounded off to the nearest hundredths.
