<span>The pair of integers that I chose are:
(a) sum is –3
5 + (-8) = -3
(b) difference is –5
2 - 7 = -5
(c) difference is 2
14 -12 = 2
(d) sum is 0
2 - 2 = 0</span>
We use the z statistic:
z = (x – u) / s
But first let us calculate the standard deviation s,
sample x and mean u.
s = sqrt (n p q)
s = sqrt (112 * 0.77 * (1 – 0.77))
s = 4.45
x = 0.81 * 112 = 90.72
u = 0.77 * 112 = 86.24
So the z score is:
z = (90.72 – 86.24) / 4.45
z = 1.00
From the standard tables, the P value at z = 1.00 using
right tailed test is:
<span>P = 0.1587 = 15.87%</span>
This is something you'll need a T table for, or a calculator that can compute critical T values. Either way, we have n = 10 as our sample size, so df = n-1 = 10-1 = 9 is the degrees of freedom.
If you use a table, look at the row that starts with df = 9. Then look at the column that is labeled "95% confidence"
I show an example below of what I mean.
In that diagram, the row and column mentioned intersect at 2.262 (which is approximate). This value then rounds to 2.26
<h3>
Answer: 2.26</h3>
Answer:
There is a 54% chance that the Jets will win the Stanley Cup.
Step-by-step explanation:
Since two hockey teams, the Winnipeg Jets and the Toronto Maple Leafs, miraculously make it to the Stanley Cup finals, where as soon as a team wins 3 games, the championship is over, and the schedule for the playoffs for home games is: Jets - Leafs - Jets - Leafs - Jets; since if the Jets are playing at home, there is a 60% chance they'll win, while if they are playing on the road, there is a 45% chance they'll win, to find the probability that the Jets win the Stanley Cup the following calculation must be performed:
(0.60 + 0.45 + 0.60 + 0.45 + 0.60) / 5 = X
2.70 / 5 = X
0.54 = X
Thus, there is a 54% chance that the Jets will win the Stanley Cup.
S(t) = -4.9t^2 + 19.6t + 24.5
when it reaches the ground s(t) = 0
so we have -4.9t^2 + 19.6t + 24.5 = 0
solve this for t:-
-4.9(t^2 - 4t - 5) = 0
(t + 1)(t - 5) = 0
so required time t = 5 seconds
answer 5 seconds
