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2 years ago

A piper delivers 9.98 g of water at 19 degrees Celsius. What does the pipet deliver

Chemistry

2 answers:

leva [86]2 years ago

5 0

Answer:

the volume = 9.99 ml

Explanation:

in your Q we need to calculate the volume does the pipet deliver so , we are going to use this formula:

the volume = mass / density

here we need to know the density of water at a certain temperature 19 degrees Celsius ,so I used an external source to get the density of water at 19 degrees Celsius because it is changing with different temperatures

where mass here = 9.98 g

and the density of water at temperature 19 degrees Celsius= 0.998405mL

-1

by substitution :

the volume = 9.98 g / 0.998405mL

-1

≅ 9.996 ml = 10 ml

yuradex [85]2 years ago

5 0

Answer:

9.99 ml water will be delivered from pipet

Explanation:

When Water is being delivered by the pipet the temperature is 19 degree Celsius. Also know that dependence of density is on temperature although this temperature dependence is inverse in nature that is when temperature increases density decreases and vice versa.

Now we also know the density of water at 20 ° Is $0.99 gml-1$ .

At this temperature 9.98 gram will occupy a volume= $0.98/0.998= 9.997ml$

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How many total atoms are in 0.670 g of p2o5?

scoray [572]

The molecular formula for compound is $P_{2}O_{5}$ mass of compound is 0.670 g.

To calculate number of atoms first calculate number of moles in the compound as follows:

$n=\frac{m}{M}$

Molar mass of $P_{2}O_{5}$ is 283.886 g/mol, thus,

$n=\frac{0.670 g}{283.886 g/mol}=0.00236 mol$

Thus, number of mole of $P_{2}O_{5}$ is 0.00236 mol.

From the molecular formula 1 mole of $P_{2}O_{5}$ has 2 mol of P (phosphorus) and 5 mol of O (oxygen).

Thus, number of moles of P and O in 0.00236 mol of $P_{2}O_{5}$ will be:

$n_{P}=2\times 0.00236 mol=0.00472 mol$

Similarly,

$n_{O}=5\times 0.00236 mol=0.0118 mol$

Now, in 1 mol of an element there are $6.023\times 10^{23}$ atoms.

Number of atoms of P will be:

$N_{P}=0.00472\times 6.023\times 10^{23}=2.84\times 10^{21}atoms$

Similarly, number of atoms of O will be:

$N_{O}=0.0118\times 6.023\times 10^{23}=7.11\times 10^{21}atoms$

Total number of atoms will be sum of number of atoms of P and O:

$N_{Total}=N_{P}+N_{O}=2.84\times 10^{21}+7.11\times 10^{21}=9.95\times 10^{21} atoms$

Therefore, total number of atoms in $P_{2}O_{5}$ will be $9.95\times 10^{21} atoms$ .

8 0

2 years ago

What is the IUPAC name of the following compound?

pentagon [3]

Answer:

(d) 3,7-dimethyl-4-nonyne.

Explanation:

Hello,

In this case, considering the attached picture on which you can see that the main chain has nine carbon atoms, one tripe bond at the fourth carbon and two methyl radicals at the third and seventh carbons respectively, by following the IUPAC rules, the name would be: (d) 3,7-dimethyl-4-nonyne since the chain must start at the side closest to the first triple bond due to its priority and subsequently considering the present radicals.

Best regards.

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2 years ago

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MrRissso [65]

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Answer:

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ankoles [38]

<span>According to my knowledge, I feel the answer is -
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Hope this helps!
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