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2 years ago

Given that Ray B A bisects ∠DBC, which statement must be true? m∠ABD = m∠ABC AB ≅ BC B is the midpoint of DC. m∠DBC = 90°

Mathematics

2 answers:

Sloan [31]2 years ago

8 0

Answer:

Step-by-step explanation:

Because I said this was the answer. I know all.

nadya68 [22]2 years ago

4 0

Answer:

A. $m\angle ABD=m\angle ABC$

Step-by-step explanation:

We are given that a ray BA bisects angle DBC.

We have to find true statement .

Angle bisector property:When a ray bisect any angle then the angles made by bisection of angle are equal.

When ray BA bisects angle DBC

Then, $m\angle ABD=m\angle ABC$

By angle bisector property.

Therefore, option A is true.

Answer:A. $m\angle ABD=m\angle ABC$

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A sociologist wants to determine if the life expectancy of people in africa is less than the life expectancy of people in asia.

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The sample statistics are attached.

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The alternative hypothesis should be: $H_{a}: u_{africa}$

The next step is about calculating the t statistics based on the samples. This t test will give the probability value or p-value, which determines if there's enough to reject the null hypothesis. The formula we need to use to find the t-value is: $t=\frac{x_{1}-x_{2} }{\sqrt{\frac{s_{1} ^{2} }{n_{1} } +\frac{s_{2} ^{2} }{n_{2} } } }$

Replacing all the values into the formula, we have:

$t=\frac{52.4-58.1}{\sqrt{\frac{(7.4)^{2} }{45}+\frac{(8.8)^{2} }{35} } } \\t=\frac{-5.7}{\sqrt{1.2+2.2} } =\frac{-5.7}{1.8} =-3.2$

Therefore, the t-value is -3.2.

Now, we using a level of significance of 0.01, and a degree of freedom (df) of 34, we use the t-table to find the p-value for this results. (df = N -1; in this case, we take the smaller sample, which is 35, giving us 34 of df).

Therefore, according to the table attached, the p-value is less than 0.01, which is less than our level of significance. This result means that the null hypothesis is rejected. In other words, there's enough evidence to say that the life expectancy of people in Africa is less than the life of expectancy of people in Asia.

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