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GrogVix [38]
2 years ago
3

A 0.21 m3 (55 gal) drum contains 100 L of a mixture of several degreasing solvents in water. The concentration of trichloroethyl

ene in the headspace (gas phase) above the water was measured to be 0.00301 atm. The Henry’s constant for trichloroethylene is 0.00985 atm·m3·mol-1 at 25°C. What is the concentration of trichloro-ethylene in the water in units of molarity? (Assume that the temperature of the solution is 25°C.)
Chemistry
1 answer:
Vikki [24]2 years ago
3 0

Answer:

0,0003 M

Explanation:

Henry's Law states that <em>the solubility of a gas in a liquid is proportional to the pressure of the gas over the solution</em>. It's equation can be written as:

                                            KC = P

where:

  • K: Henry's constant at a given temperature [atm.L/mol]
  • C: molarity of the gas in the liquid phase [mol/L]
  • P: pressure of the gas in the gas phase [atm]

To solve the problem, we replace the data in Henry's Law equation using the appropiate units.

<em>1) Changing our data to appropiate units:</em>

K = 0,00985 atm.m3/mol * (1000 L/1 m3) = 9,85 atm.L/mol

P = 0,00301 atm/1 atm = 0,00301

<em>2) Clearing the incognita:</em>

KC=P................. C=P/K

<em>3) Replacing our values:</em>

C=0,00301 atm/9,85 atm.L/mol = 0.0003 mol/L = 0,0003 M

<em>4) Answer:</em>

The concentration of  trichloro-ethylene in the water is 0,0003 M

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  • The combustion of propane is definitely an exothermic reaction because it generates a lot of heat.

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What mitigation measures can communities do to reduce the damage and impact of sudden geologic hazards?
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What is the change in enthalpy in kilojoules when 3.24 g of CH3OH is completely reacted according to the following reaction 2 CH
vodka [1.7K]

Answer:

12.78 kJ

Explanation:

The correct balanced reaction would be

2CH_3OH\rightarrow 2CH_4+O_2\Delta H=252.8\ \text{kJ}

Mass of methanol = 3.24\ \text{g}

Moles of methanol can be obtained by dividing the mass of methanol with its molar mass (32.04\ \text{g/mol})

\dfrac{3.24}{32.04}=0.10112\ \text{moles}

Enthalpy change for the number of moles is given by

\dfrac{\text{Number of moles of methanol in the reaction}}{\text{Enthalpy change in the reaction}}=\dfrac{\text{Number of moles in 3.24 g of methanol}}{\text{Enthaply in change in the mass of methanol}}

\\\Rightarrow\dfrac{2}{252.8}=\dfrac{0.10112}{\Delta H}\\\Rightarrow \Delta H=\dfrac{0.10112\times 252.8}{2}\\\Rightarrow \Delta H=12.781568\approx 12.78\ \text{kJ}

The change in enthalpy is 12.78 kJ.

5 0
2 years ago
A solution has a hydroxide-ion concentration of 0.0040 M. What is the pOH of the solution? A solution has a pH value of 3.66. Wh
hodyreva [135]

Answer:

1. pOH = 2.4

2. pOH = 10.34

3. pH = 2.14

Explanation:

1. Determination of the pOH.

Concentration of Hydroxide ion, [OH-] = 0.004 M

pOH =?

pOH = - log [OH-]

pOH = - log (0.004)

pOH = 2.4

Therefore, the pOH of the solution is 2.4

2. Determination of the pOH.

pH = 3.66

pOH =?

pH and pOH are related by the following equation:

pH + pOH = 14

With the above formula, we can obtain the pOH of the solution as follow:

pH = 3.66

pOH =?

pH + pOH = 14

3.66 + pOH = 14

Collect like terms

pOH = 14 - 3.66

pOH = 10.34

Therefore, the pOH of the solution is 10.34

3. Determination of the pH.

Molarity of HCl = 0.0072 M

Concentration of Hydrogen ion, [H+] =?

Thus, we can obtain the concentration of Hydrogen ion, [H+] as follow:

HCl(aq) —> H+(aq) + Cl-(aq)

From the balanced equation above,

1 mole of HCl produced 1 mole of H+.

Therefore, 0.0072 M HCl will also produce 0.0072 M H+.

Therefore, the concentration of Hydrogen ion, [H+] in the solution is 0.0072 M.

Finally, we shall determine the pH of the solution as follow:

Concentration of Hydrogen ion, [H+] = 0.0072 M.

pH =?

pH = - log [H+]

pH = - log (0.0072)

pH = 2.14

Therefore, the pH of the solution is 2.14

3 0
2 years ago
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