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aleksklad [387]
2 years ago
11

Jeff and Kayla are finding the product of 178 times 56.They both are using the distributive property to find partial products.Lo

ok at their work below.
Mathematics
1 answer:
UNO [17]2 years ago
6 0

Answer:

9968

Step-by-step explanation:

178×56=178×(50+6)

=178×50+178×6

=8900+(170+8)×6

=8900+170×6+8×6

=8900+1020+48

=9968

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The diameter of circle measure 18mm.what is the circumference of the circle?​
ziro4ka [17]

Answer:

18π mm

Step-by-step explanation:

C=2πr

d=2r, 18=2r, r=9

C=18π mm

4 0
1 year ago
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Please help. Find the length of the side labeled x. Round intermediate values ​​to the nearest thousandth. Use the rounded value
Vaselesa [24]
19)18.7 20)7.9
21)13.3 22)102.4
5 0
1 year ago
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Worth 80 points!! It's alot for me to understand and i wanna get it right someone help?
Mandarinka [93]

Add all the new budget amounts:

510 + 254 + 295 + 51 + 0 + 100 + 100+ 0 + 100 = 1410


Her monthly total is 1410, which is less than her income of 1700

1700 - 1410 = 290

She has $290 extra each month.

So she can divide that amount by 2 to put an equal amount in each blank category, or add what ever amount less than that into each one.


4 0
1 year ago
Michael invests USD 20 000 at 9.6% p.a. compounded monthly.
alexandr1967 [171]

Given :

A = 25000

P = 20000

r % = 9.6 % = 0.096

n = 12

To Find :

The time taken say t.

Solution :

We know, compound interest is given by :

A=P(1+\dfrac{r}{n})^{n.t}

Taking log both sides :

A=P(1+\dfrac{r}{n})^{n.t}\\\\log\ \dfrac{A}{P}= n.t\times log( 1+\dfrac{r}{n})\\\\t =\dfrac{1}{n}\times \dfrac{log\ \dfrac{A}{P}}{log(1+\dfrac{r}{n})}\\\\\\t=\dfrac{1}{12}\times \dfrac{log\ \dfrac{25000}{20000}}{log(1+\dfrac{0.096}{12})}\\\\\\t=2.33\ years

Hence, this is the required solution.

5 0
2 years ago
g In a survey of 500 residents, 300 were opposed to the use of the photo-cop for issuing traffic tickets.The standard error of t
Evgesh-ka [11]

Answer:

Z-score 1.96

Margin of error d= 0.04323

Step-by-step explanation:

Hello!

The study variable in this case is

X: Number of people that oppose the use of photo-cop for issuing traffic tickets in a sample of 500.

n= 500

The parameter of interest is the proportion of people that opposes it.

The estimated proportion is p'= 300/500= 0.6

To estimate the population proportion per Confidence interval you have to approximate the distribution of the sample proportion p' to normal:

p'≈N(p;p(1-p)1/n)

The mean of this distribution is p and the variance is p*(1-p)*1/n

To construct the Confidence interval, since the value of the population proportion is unknown, an estimated variance is used:

p'(1-p')*1/n ⇒ then the estimated standard error is √(p'(1-p')*1/n)

The formula for the confidence interval is:

p' ± Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }

Where "Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }" represents the margin of error of the interval.

Now for a confidence level of 0.95 the value of Z is Z_{0.975}= 1.965

The estimated standard error is already calculated: \sqrt{\frac{p'(1-p')}{n} } = 0.022

The margin of error (d) is then:

d= Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }= 1.965 * 0.022

d= 0.04323

I hope it helps!

7 0
1 year ago
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