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HACTEHA [7]
2 years ago
4

Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar.

Mathematics
1 answer:
Papessa [141]2 years ago
7 0

Answer:

The first solution is (-6, 29), and the second is (4, -11).

Step-by-step explanation:

Rewrite the 2nd equation as y = -4x + 5.  Then the first equation becomes:

                                                   = -4x + 5 = x^2 - 2x - 19.

This equation has only one variable:  x.  Rewriting this equation in the standard form of a quadratic, we get:

                                                               0 = x^2 + 2x - 24

and this quadratic can be factored into 0 = (x - 4)(x + 6), whose roots are

{-6, 4}.  This agrees with one of the two points mentioned in the problem:

(-6, 29) is a solution.  What's the other one?  

We have just found that the 2 roots are {-6, 4}.  Then the missing root is 4, and the y-value there is found from y + 4x = 5:

y = -4x + 5, which here is y = -4(4) + 5, or  y = -16 + 5, or y = -11.

The first solution is (-6, 29), and the second is (4, -11).

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The average American man consumes 9.8 grams of sodium each day. Suppose that the sodium consumption of American men is normally
Alex Ar [27]

Answer:

(a) The distribution of <em>X</em> is <em>N</em> (9.8, 0.8²).

(b) The probability that an American consumes between 8.8 and 9.9 grams of sodium per day is 0.4461.

(c) The middle 30% of American men consume between 9.5 grams to 10.1 grams of sodium.

Step-by-step explanation:

The random variable <em>X</em> is defined as the amount of sodium consumed.

The random variable <em>X</em> has an average value of, <em>μ</em> = 9.8 grams.

The standard deviation of <em>X</em> is, <em>σ</em> = 0.8 grams.

(a)

It is provided that the sodium consumption of American men is normally distributed.

The random variable <em>X</em> follows a normal distribution with parameters <em>μ</em> = 9.8 grams and <em>σ</em> = 0.8 grams.

Thus, the distribution of <em>X</em> is <em>N</em> (9.8, 0.8²).

(b)

If X ~ N (µ, σ²), then Z=\frac{X-\mu}{\sigma}, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z ~ N (0, 1).

To compute the probability of  Normal distribution it is better to first convert the raw score (<em>X</em>) to <em>z</em>-scores.

Compute the probability that an American consumes between 8.8 and 9.9 grams of sodium per day as follows:

P(8.8

                           =P(-1.25

Thus, the probability that an American consumes between 8.8 and 9.9 grams of sodium per day is 0.4461.

(c)

The probability representing the middle 30% of American men consuming sodium between two weights is:

P(x_{1}

Compute the value of <em>z</em> as follows:

P(-z

The value of <em>z</em> for P (Z < z) = 0.65 is 0.39.

Compute the value of <em>x</em>₁ and <em>x</em>₂ as follows:

-z=\frac{x_{1}-\mu}{\sigma}\\-0.39=\frac{x_{1}-9.8}{0.8}\\x_{1}=9.8-(0.39\times 0.8)\\x_{1}=9.488\\x_{1}\approx9.5     z=\frac{x_{2}-\mu}{\sigma}\\0.39=\frac{x_{1}-9.8}{0.8}\\x_{1}=9.8+(0.39\times 0.8)\\x_{1}=10.112\\x_{1}\approx10.1

Thus, the middle 30% of American men consume between 9.5 grams to 10.1 grams of sodium.

4 0
2 years ago
The dye dilution method is used to measure cardiac output with 3 mg of dye. The dye concentrations, in mg/L, are modeled by c(t)
Lemur [1.5K]

Answer:

Cardiac output:F=0.055 L\s

Step-by-step explanation:

Given : The dye dilution method is used to measure cardiac output with 3 mg of dye.

To Find : Find the cardiac output.

Solution:

Formula of cardiac output:F=\frac{A}{\int\limits^T_0 {c(t)} \, dt} ---1

A = 3 mg

\int\limits^T_0 {c(t)} \, dt =\int\limits^{10}_0 {20te^{-0.06t}} \, dt

Do, integration by parts

[\int{20te^{-0.6t}} \, dt]^{10}_0=[20t\int{e^{-0.6t} \,dt}-\int[\frac{d[20t]}{dt}\int {e^{-0.6t} \, dt]dt]^{10}_0

[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20}{0.6}\int {e^{-0.6t} \,dt]^{10}_0

[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20e^{-0.6t}}{(0.6)^2}]^{10}_{0}

[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-200e^{-6}}{0.6}+\frac{20e^{-6}}{(0.6)^2}]+\frac{20}{(0.60^2}

[\int{20te^{-0.6t}} \, dt]^{10}_0=\frac{20(1-e^{-6}}{(0.6)^2}-\frac{200e^{-6}}{0.6}

[\int{20te^{-0.6t}} \, dt]^{10}_0\sim {54.49}

Substitute the value in 1

Cardiac output:F=\frac{3}{54.49}

Cardiac output:F=0.055 L\s

Hence Cardiac output:F=0.055 L\s

4 0
2 years ago
How can Ari simplify the following expression? StartFraction 5 Over a minus 3 EndFraction minus 4 divided by 2 + StartFraction 1
Zielflug [23.3K]

Answer:

-\frac{8}{3}

Step-by-step explanation:

Given

\frac{5}{-3} - \frac{4}{2} + \frac{1}{-3}

Required

Simpify

The very first step is to take LCM of the given expression

\frac{-10 -4 - 2}{6}

Perform arithmetic operations o the numerator

-\frac{16}{6}

Divide the numerator and denominator by 2

-\frac{16/2}{6/2}

-\frac{8}{3}

The expression can't be further simplified;

Hence, \frac{5}{-3} - \frac{4}{2} + \frac{1}{-3} = -\frac{8}{3}

8 0
2 years ago
Which of the x values are solutions to the inequality 4(2 – x) &gt; –2x – 3(4x + 1)? Check all that apply.
steposvetlana [31]
4(2 - x) > -2x - 3(4x + 1)
8 - 4x > -2x - 12x - 3
-4x + 2x + 12x > -3 - 8
10x > -11
x > -11/10
x > -1.1

Therefore, x = 0 and x = 10 zre solutions to the inequality.
4 0
2 years ago
Read 2 more answers
After watching the video below, explain what is happening in your own words. What percent of the original dollar size will the 4
RSB [31]

Answer:

is there an image or something idk the vid

6 0
2 years ago
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