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cestrela7 [59]
2 years ago
6

There are two kinds of elements that didn't appear on the periodic table until after 1892. What kinds are they and why do you th

ink it took so long to discover them?
Chemistry
2 answers:
rosijanka [135]2 years ago
6 0

Answer:

The two elements are Argon and Helium .

They are noble gas  and are not reactive

Explanation:

The two kinds of element are argon and helium. These two element were discovered in 1892 by a Scottish chemist Williams Ramsay.

These two elements are known as noble gas or inert gas  because of how hard they find it to react with other elements.

Elements back then were discovered through their reactivity with other elements but It took so long to discover these elements(argon and helium) because of their unreactive nature . Combine with the fact that they were odorless, tasteless and colorless it was more hard to discover them.

Lelu [443]2 years ago
5 0

Your Question: There are two kinds of elements that didn't appear on the periodic table until after 1892. What kinds are they and why do you think it took so long to discover them?

The Answer: Moseley’s analysis enabled chemists to refine the table further  and reveal more gaps, which suggested that there were more new  elements waiting to be discovered, with atomic numbers 43, 61, 72  and 75. Scientists subsequently found these elements—now  known as technetium, promethium, hafnium and rhenium,  respectively.

Explanation: Physicist Henry Moseley discovered the atomic number of each element using x-rays, which led to more accurate organization of the periodic table. We will cover his life and discovery of the relationship between atomic number and x-ray frequency, known as Moseley's Law.

Remember to read study guides, lessons and notes to rely yourself on; key to success is working hard. Good Luck!

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A flask contains 0.180 mol of liquid bromine, br2. determine the number of bromine molecules present in the flask.
Reika [66]
<span>Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles. We calculate as follows:

0.180 mol Br2 ( </span>6.022 x 10^23 molecules / mole ) = 1.084x10^23 molecules Br2
5 0
2 years ago
Read 2 more answers
A 2.20 g sample of a compound gave 5.63 g CO2 and 2.30 g H2O on combustion in air. The compound is known to contain only C, H, O
ICE Princess25 [194]

The simplest formula is C₅H₁₀O.

We must calculate the masses of C, H, and O from the masses given.

<em>Mass of C</em> =5.63 g CO₂ × (12.01 g C/44.01 g CO₂) = 1.536 g C

<em>Mass of H</em> = 2.30 g H₂O × (2.016 g H/18.02 g H₂O) = 0.2573 g H

<em>Mass of O</em> = Mass of compound - Mass of C - Mass of H

= (2.20 – 1.536 – 0.2573) g = 0.406 g

Now, we must convert these masses to moles and find their ratios.

From here on, I like to summarize the calculations in a table.

<u>Element  Mass/g    Moles     Ratio    Integers </u>

     C         1.536     0.1279     5.038        5

     H       0.2573    0.2553  10.05         10

     O       0.406      0.0254    1                 1

The empirical formula is C₅H₁₀O.

7 0
2 years ago
calculate the water potential of a solution of 0.15m sucrose. the solution is at standard temperature.
Mrac [35]

Answer:

The water potential of a solution of 0.15 M sucrose solution is -3.406 bar.

Explanation:

Water potential = Pressure potential + solute potential

P_w=P_p+P_s

P_w=P_p+(-iCRT)

We have :

C = 0.15 M, T = 273.15 K

i = 1

The water potential of a solution of 0.15 m sucrose= P_w

P_p=0 bar (At standard temperature)

P_s=-iCRT=-\times 1\times 8.314\times 10^{-2}bar L/mol K\times 273.15 K=-3.406 bar

P_w=0 bar+(-3.406 ) bar

The water potential of a solution of 0.15 M sucrose solution is -3.406 bar.

7 0
2 years ago
Consider these generic half-reactions. Half-reaction E° (V) X+(aq)+e−⟶X(s) 1.52 Y2+(aq)+2e−⟶Y(s) −1.17 Z3+(aq)+3e−⟶Z(s) 0.84 Ide
olya-2409 [2.1K]

Answer:

     strongest oxidizing agent: X^{+}

     weakest oxidizing agent: Y^{2+}

     strongest reducing agent: Y

     weakest reducing agent: X

     X^{+} will oxidize Z

Explanation:

The higher the reduction potential of a species, higher will be the tendency to consume electrons from another species. Hence higher will be the oxidizing power of it's oxidized form and lower will be the reducing power of it's reduced form.

Alternatively, higher reduction potential value suggests that the oxidized form of the species acts as a stronger oxidizing agent and the reduced form of the species acts as a weaker reducing agent.

Order of reduction potential:

                       E_{X^{+}\mid X}^{0}(1.52V)> E_{Z^{3+}\mid Z}^{0}(0.84V)> E_{Y^{2+}\mid Y}^{0}(-1.17V)

So, strongest oxidizing agent: X^{+}

     weakest oxidizing agent: Y^{2+}

     strongest reducing agent: Y

     weakest reducing agent: X

As reduction potential of the half cell X^{+}\mid X is higher than the reduction potential of the half cell Z^{3+}\mid Z therefore X^{+} will oxidize Z into Z^{3+} and itself gets converted into X.

     

5 0
2 years ago
How do moss leaves and fish differ? How are they the same?
Lapatulllka [165]
Moss leaves and fish are different in that, the moss leave is a producer, that is, it produces its own food through photosynthesis while the fish is a consumer, it feeds on foods that are not produced by it.  
Both moss and fish are the same in the sense that both have cell as their basic unit of life, that is, they both possess cells.
4 0
2 years ago
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