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2 years ago

Assuming the following materials will not mix,show how the materials would "Stack up" in a graduated cylinder.

Chemistry

1 answer:

mihalych1998 [28]2 years ago

4 0

Answer:

Density is mass per unit volume.

Its formula is

Density = Mass / Volume

Its units can be kg/L or kg/( $dm^3$ ) or g/mL or g/( $cm^3$ )

Density of various substances are given. The more denser substance goes to the bottom of the graduated cylinder.

Air on the top then comes Wood followed by Corn oil followed by Ice and then Water followed by Glycerin then Rubber then Corn syrup and at last Steel at the bottom which will more denser than all the substances mentioned above.

The staking up of the substances is in the order mentioned below in the tabular column

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A sample contains 2.2 g of the radioisotope niobium-91 and 15.4 g of its daughter isotope, zirconium-91. how many half-lives hav

dybincka [34]

Answer: 3

Explanation: This is a radioactive decay and all the radioactive process follows first order kinetics.

Equation for the reaction of decay of $_{19}^{40}\textrm{K}$ radioisotope follows:

$Moles of zirconium=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{15.4}{91}=0.17moles$

$Moles of niobium=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{2.2}{91}=0.024moles$

$_{41}^{91}\textrm{Nb}\rightarrow _{40}^{91}\textrm{Zr}+_{+1}^0e$

By the stoichiometry of above reaction,

1 mole of $_{40}^{91}\textrm{Zr}$ is produced by 1 mole $_{41}^{91}\textrm{Nb}$

So, 0.17 moles of $_{40}^{91}\textrm{Zr}$ will be produced by = $\frac{1}{1}\times 0.17=0.17\text{ moles of }_{40}^{91}\textrm{Nb}$

Amount of $_{82}^{212}\textrm{K}$

decomposed will be = 0.17 moles

Initial amount of $_{40}^{91}\textrm{Nb}$ will be = Amount decomposed + Amount left = (0.17 + 0.024)moles =0.194 moles

$a=\frac{a_o}{2^n}$

where,

a = amount of reactant left after n-half lives = 0.024

$a_o$ = Initial amount of the reactant = 0.194

n = number of half lives= ?

Putting values in above equation, we get:

$0.024=\frac{0.194}{2^n}$

$n=3$

Therefore, 3 half lives have passed.

3 0

2 years ago

Read 2 more answers

Aqueous hydrochloric acid reacts with aqueous sodium sulfite to produce aqueous sodium chloride and aqueous sulfurous acid. Writ

ohaa [14]

Answer:

2HCl(aq) + Na2SO3(aq) —> 2NaCl(aq) + H2SO3(aq)

Explanation:

HCl(aq) + Na2SO3(aq) —> NaCl(aq) + H2SO3(aq)

Let us balance the equation. This is illustrated below:

There are 2 atoms of Na on the left side of the equation and 1atom on the right side. It can be balance by putting 2 in front of NaCl as shown below:

HCl(aq) + Na2SO3(aq) —> 2NaCl(aq) + H2SO3(aq)

Now, we have 2 atoms of Cl on the right side and 1 atom on the left side. Thus, it can be balance by putting 2 in front of HCl as shown below:

2HCl(aq) + Na2SO3(aq) —> 2NaCl(aq) + H2SO3(aq)

A careful look at the equation proved that the equation is balanced as the numbers of the different atoms of the element on both side of the equation are the same.

4 0

2 years ago

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What is the molarity of a solution that is made by adding 57.3 g of MgO to 500.0 mL of solution?

kifflom [539]

Answer:

2.843 M

Explanation:

Molarity = moles / volume

Milliliters to liters:

500 mL = .500 L

Grams to moles:

MgO molar mass = 16.00 + 24.31 = 40.31 g/mol

57.3 g x 1 mol / 40.31 g = 1.421 mol

Molarity:

1.421 mol / .500 L = 2.843 M

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2 years ago

How many atoms of nitrogen are in 1.2 grams of aspartame?

qaws [65]

The molecular formula for aspartame is C14H18N2O5, and its molar mass is about 294 g/mol.

Convert 1.2 g into moles, which gives

1.2 g / 294 g/mol = 4.08 X 10-3 moles aspartame.

Since each mole of aspartame has 2 moles of nitrogen, you have 8.16 X 10-3 moles of N in your 1.2 grams of aspartame.

Finally, multiply that by Avogadro's number to get the number of N atoms:

8.16 X 10^-3 mol X 6.02 X 10^23 = 4.9 X 10^21 nitrogen atoms.

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Which diastereomer of oct−4−ene yields a single meso compound, (4r, 5s)−4,5−dibromooctane on reaction with br2?

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