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erastovalidia [21]
2 years ago
10

We have two equal size boxes, A and B. Each box contains gas that behaves as an ideal gas. We insert a thermometer into each box

and find that the gas in box S is at a temperature of 50°C while that in B is at 10°C. This is all we know about the gas in the boxes. Which of the following statements MUST be true? Which COULD be true? Explain the reasoning behind your answers.
a) The pressure in A is higher than in B
b) There are more molecules in A than in B
c) A and B cannot contain the same type of gas
d) The molecules in A have more average kinetic energy per molecule than those in B
e) The molecules in A are moving faster than those in B
Physics
1 answer:
AlekseyPX2 years ago
5 0

Answer:

d) The molecules in A have more average kinetic energy per molecule than those in B

e) The molecules in A are moving faster than those in B

Explanation:

Given that

Size of boxes are equal

So volume of boxes = V

Temperature in box A =50°C = 323 k

Temperature in box B = 10°C = 283 K

We know that for ideal gas

P V = m R T

The mass of gases is not given so we can not say that which have high temperature.Also be can not say that which box have more molecule.

We know that average kinetic energy is directly proportional to the absolute temperature of gas that is why we can say that box A will have more kinetic energy because it have high temperature.We know that is gas have high kinetic energy then we can say that it have high moving velocity.

So the option d and e is correct.

d) The molecules in A have more average kinetic energy per molecule than those in B

e) The molecules in A are moving faster than those in B

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A physics student stands on the rim of the canyon and drops a rock. The student measures the time for it to reach the bottom to
madam [21]

Answer:

Canyon is 50.176 meter deep.

Explanation:

The students is standing on the rim of the canyon and drops down a rock from the rim(cliff). We have to find what is the depth of the canyon i.e. how much below is the ground from the cliff.

Given data:

Time = t = 3.2 s

Initial velocity = v_{i} = 0 m/s

Gravitational acceleration = g = 9.8 m/s²

Height = h = ?

According to second equation of motion

h = v_{i}t + \frac{1}{2}gt^{2}

As initial velocity is zero, So the first term of right hand side of above equation equal to zero

h = \frac{1}{2}gt^{2}

h = (0.5)(9.8)(3.2)²

h = 50.176 m

This means, the rock traveled 50.176 meters to reach the bottom of the Canyon. So, the Canyon is 50.176 meter deep.

5 0
2 years ago
A couch is pushed with a horizontal force of 80 N and moves the couch a
Lapatulllka [165]

Answer:

400 J

Explanation:

Work = force × distance

W = (80 N) (5 m)

W = 400 J

5 0
2 years ago
Read 2 more answers
A student is conducting a physics experiment and rolls four different-
joja [24]

Answer:

<em>I think the answer is C</em>

<em />

Explanation:

Its heavy but not too heavy

4 0
2 years ago
On a warm summer day (31 ∘c), it takes 4.60 s for an echo to return from a cliff across a lake. on a winter day, it takes 5.00 s
xenn [34]
The question is missing, but I guess the problem is asking for the distance between the cliff and the source of the sound.

First of all, we need to calculate the speed of sound at temperature of T=31^{\circ}C:
v=(331+0.60 T) m/s = (331+0.6 \cdot 31) m/s = 349.6 m/s

The sound wave travels from the original point to the cliff and then back again to the original point in a total time of t=4.60 s. If we call L the distance between the source of the sound wave and the cliff, we can write (since the wave moves by uniform motion):
v= \frac{2L}{t}
where v is the speed of the wave, 2L is the total distance covered by the wave and t is the time. Re-arranging the formula, we can calculate L, the distance between the source of the sound and the cliff:
L= \frac{vt}{2}= \frac{(349.6 m/s)/4.60 s)}{2}=  804.1 m
6 0
2 years ago
When boiling water, a hot plate takes an average of 8 minutes and 55 seconds to boil 100 milliliters of water. Assume the temper
alexandr1967 [171]

Answer:

90.9 seconds

Explanation:

m = Mass of liquid = Volume×Density

c = Specific heat

\Delta T = Change in temperature

t = Time taken

Room temperature = 75 °F

Converting to Celsius

(75-32)\times \frac{5}{9}=23.889\ ^{\circ}C

Heat required to raise the temperature of water

Q=mc\Delta T\\\Rightarrow Q=100\times 10^{-6}\times 1000\times 4186\times (100-23.889)\\\Rightarrow Q=31860.0646\ J

Power

P=\frac{Q}{t}\\\Rightarrow P=\frac{31860.0646}{8\times 60+55}\\\Rightarrow P=59.55152\ W

Efficiency of the plate

\frac{59.5512}{283}\times 100=21.04282\%

Heat required to raise the temperature of water

Q=mc\Delta T\\\Rightarrow Q=100\times 10^{-6}\times 784\times 2150\times (56-23.889)\\\Rightarrow Q=5412.63016\ J

P=\frac{Q}{t}\\\Rightarrow t=\frac{Q}{P}\\\Rightarrow t=\frac{5412.63016}{0.2104282\times 283}\\\Rightarrow t=90.9\ s

Time taken to heat the aceton is 90.9 seconds

4 0
2 years ago
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