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sukhopar [10]
2 years ago
15

n a presentation about measuring mass, one of your classmates states, "Two objects of the same size will always have the same ma

ss.” Is this statement correct? Why or why not?
Physics
2 answers:
Liono4ka [1.6K]2 years ago
5 0

Answer:

Sample Response: Different objects contain different amounts of matter, even if they are the same size. Therefore, two objects of the same size can have different masses.

Hi I know im late on this but for people who are looking for the answer.

Neporo4naja [7]2 years ago
4 0
Answer:
The statement is not correct.

Reason:
If two objects have the same mass, their respective densities determine their volumes.
By definition,
density = mass/volume.
or volume = mass/density.

Therefore if two objects have the same mass, the mode dense object (with higher density) will occupy less volume than the other object.

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A car of mass 1100kg moves at 24 m/s. What is the braking force needed to bring the car to a halt in 2.0 seconds? N
LenaWriter [7]

13200N

Explanation:

Given parameters:

Mass = 1100kg

Velocity = 24m/s

time = 2s

unknown:

Braking force = ?

Solution:

The braking force is the force needed to stop the car from moving.

   Force  =  ma = \frac{mv}{t}

  m is the mass of the car

  v is the velocity

  t is the time taken

  Force = \frac{1100 x 24}{2} = 13200N

Learn more:

Force brainly.com/question/4033012

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8 0
2 years ago
What's the momentum of a 3.5-kg boulder rolling down hill at 5 m/s
ICE Princess25 [194]
P = mv 
p = 3.5 × 5 
p = 17.5 kg .m/s

Hope this helps!
6 0
2 years ago
Inna Hurry is traveling at 6.8 m/s, when she realizes she is late for an appointment. She accelerates at 4.5 m/s^2 for 3.2 s. Wh
Alborosie

Answer:

1) v = 21.2 m/s

2) S = 63.33 m

3) s = 61.257 m

4) Deceleration, a = -4.32 m/s²

Explanation:

1) Given,

The initial velocity of Inna, u = 6.8 m/s

The acceleration of Inna, a = 4.5 m/s²

The time of travel, t = 3.2 s

Using the first equation of motion, the final velocity is

                v = u + at

                   = 6.8 + 4.5 x 3.2

                   = 21.2 m/s

The final velocity of Inna is, v = 21.2 m/s

2) Given,

The initial velocity of Lisa, u = 12 m/s

The final velocity of Lisa, v = 26 m/s

The acceleration of Lisa, a = 4.2 m/s²

Using the III equations of motion, the displacement is

                          v² = u² +2aS

                         S = (v² - u²) / 2a

                            = (26² -12²) / 2 x 4.2

                            = 63.33 m

The distance Lisa traveled, S = 63.33 m

3) Given,

The initial velocity of Ed, u = 38.2 m/s

The deceleration of Ed, d = - 8.6 m/s²

The time of travel, t = 2.1 s

Using the II equations of motion, the displacement is

                        s = ut + 1/2 at²

                           =38.2 x 2.1 + 0.5 x(-8.6) x 2.1²

                           = 61.257 m

Therefore, the distance traveled by Ed, s = 61.257 m

4) Given,

The initial velocity of the car, u = 24.2 m/s

The final velocity of the car, v = 11.9 m/s

The time taken by the car is, t = 2.85 s

Using the first equations of motion,

                         v = u + at

∴                        a = (v - u) / t

                            = (11.9 - 24.2) / 2.85

                            = -4.32 m/s²

Hence, the deceleration of the car, a = = -4.32 m/s²

5 0
2 years ago
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garri49 [273]
Where are the following sketches?
7 0
2 years ago
the initial kinetic energy of an object moving on a horizontal surface is K. Friction between the object and the surface causes
Ugo [173]

Answer:

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8 0
1 year ago
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