Answer:
Explanation:
Expression for escape velocity
ve = 
ve² R / 2 = GM
M is mass of the planet , R is radius of the planet .
At distance r >> R , potential energy of object
= 
Since the object is at rest at that point , kinetic energy will be zero .
Total mechanical energy =
+ 0 = 
Putting the value of GM = ve² R / 2
Total mechanical energy = ve² Rm / 2 r
This mechanical energy will be conserved while falling down on the earth due to law of conservation of mechanical energy . So at surface of the earth , total mechanical energy
= ve² Rm / 2 r
Answer:
Straight line in the direction of the tangential velocity the ball had at the moment the string broke
Explanation:
After the string breaks, the ball now disconnected from the centripetal force that was exerted via the string, continues its travel in a straight line in the direction of the tangential velocity it had at the moment the string broke.
Answer:
The magnitude of the total linear acceleration is 0.27 m/s²
b. 0.27 m/s²
Explanation:
The total linear acceleration is the vector sum of the tangential acceleration and radial acceleration.
The radial acceleration is given by;

where;
a is the angular acceleration and
r is the radius of the circular path

Determine time of the rotation;

Determine angular velocity
ω = at
ω = 1.6 x 0.707
ω = 1.131 rad/s
Now, determine the radial acceleration

The magnitude of total linear acceleration is given by;

Therefore, the magnitude of the total linear acceleration is 0.27 m/s²
b. 0.27 m/s²
Solution for the problem is:
Total momentum before collision is always equal to total
momentum after collision. So note that:
Momentum of car A = 5000 x Xm/s
Momentum of car A + B = 15,000 x 2m/s
So combining the two, will give us the equation:
15,000/5,000 = 3
3 x 2 =6m/s
Answer:
B or It decreased by 1/4.
Explanation:
Answer for edgenuity